Word Problem: Increasing Solution Strength to 30%

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To achieve a final strength of 30% in a 90 L tank currently holding a 20% solution, 15 L of the solution should be drained and replaced with an 80% solution. The remaining solution after draining will be 90 - X liters of 20% solution, which contains 0.2(90 - X) L of the chemical. The added 80% solution contributes 0.8X L of the chemical. By setting the total chemical content equal to that of a 30% solution, the calculation shows that 15 L must be replaced. This process effectively increases the overall strength to the desired concentration.
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1. A tank holds 90 L of chemical solution. Currently the solution has a strength of 20%. How much of this should be drained and replaced with an 80% solution to have a final strength of 30%?
 
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Suppose you "drain and replace" X liters of the 20% solution. That leaves 90- X liters of 20% solution. The X liters of the 80% solution will contain 0.8X L of the chemical. The remaining 90-X liters will contain 0.2(90- X) L of the chemical so you will now have 0.8X+ 0.2(90-X) L of the chemical in the final result. How much chemical will there be in 90 L of 30% solution? Set those equal and solve for X.
 
Answer is 15 L.

thx :D
 
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