y = x^2 ,\,\,y = \frac{2}{{x^2 + 1}}
It looks obvious from the graph that the intersections are -1 and 1, but just to verify:
\frac{2}{{x^2 + 1}} = x^2 \,\, \Leftrightarrow \,\,x^2 \left( {x^2 + 1} \right) = 2\,\, \Leftrightarrow x^4 + x^2 = 2,\,\,x = - 1,\,\,1
So my...