Functional derivative Definition and 27 Threads
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A Is the functional derivative a function or a functional
I am confused whether the functional derivative ($\delta F[f]/\delta f$) is itself a functional or whether it is only a function The Wikipedia article is not very rigorous https://en.wikipedia.org/wiki/Functional_derivative but from the examples (like Thomas-Fermi density), it seems as if the... -
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Is My Understanding of Higher-Order Functional Derivatives Correct?
(To moderators: although the question is mathematical, I post it in the physics forum because the definition and the notation are those used by physicists and because it comes from a QFT textbook; please move it if I'm wrong.) My issue with this question is that the textbook has neither defined...- Hill
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- Functional derivative Mathematical physics
- Replies: 8
- Forum: Advanced Physics Homework Help
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I Definition of functional derivative
In the book Quantum Field Theory for the Gifted Amateur, they define the functional derivative as: $$ \frac{\delta F}{\delta f(x))} = \lim_{\epsilon\to 0} \frac{F[f(x') + \delta(x'-x)) ] - F[ f(x') ]}{\epsilon} $$ Why do they use the delta function and not some other arbitrary function?- PreposterousUniverse
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- Definition Derivative Functional Functional derivative
- Replies: 4
- Forum: Quantum Physics
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Doubt regarding functional derivative for the Thomas Fermi kinetic energy
I have some doubts with respect on how the functional derivative for the kinetic energy in density functional theory is obtained. I have been looking at this article in wikipedia: https://en.wikipedia.org/wiki/Functional_derivative In particular, I'm interested in how to get the...- JhonDoe
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- Derivative Doubt Energy Fermi Functional Functional derivative Kinetic Kinetic energy
- Replies: 14
- Forum: Advanced Physics Homework Help
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A Functional Derivatives in Q.F.T.
I'm can't seem to figure out how to functionally differentiate a functional such as Z(J)= e^{\frac{i}{2} \int \mathrm{d}^4y \int \mathrm{d}^4x J(y) G_F (x-y) J(x)} with respect to J(x) . I know the answer is \frac{\delta Z(J)}{\delta J(x)}= -i \int \mathrm{d}^4y J(y) G(x-y) but I'm struggling...- QFT1995
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- Derivatives Functional Functional derivative Qft
- Replies: 1
- Forum: Quantum Physics
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A Variational derivative and Euler-Poincare equations
Hi, I'm trying to understand the Euler-Poincare equations, which reduce the Euler-Lagrange equations for certain Lagrangians on a Lie group. I'm reading Darryl Holm's "Geometric mechanics and symmetry", where he suddenly uses what seems to be a variational derivative, which I'm having a hard...- eipiplusone
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- Derivative Functional derivative
- Replies: 4
- Forum: Differential Geometry
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I What are the insights into the Total Derivative formula?
I’ve always been confused by the formula for the Total Derivative of a function. $$\frac{df(u,v)}{dx}= \frac{\partial f}{\partial x}+\frac{\partial f }{\partial u}\frac{\mathrm{d}u }{\mathrm{d} x}+\frac{\partial f}{\partial v}\frac{\mathrm{d}v }{\mathrm{d} x}$$ Any insight would be greatly...- quickAndLucky
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- Calculus Derivative Differential form Functional derivative Insights Total derivative
- Replies: 6
- Forum: Calculus
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Understanding functional derivative
Homework Statement "The functional ## J[f] = \int [f(y)]^pφ(y)\, dy ## has a functional derivative with respect to ## f(x) ## given by: $$ \frac {δJ[f]} {δf(x)} = \lim_{ε \rightarrow 0} \frac 1 ε \left[ \int[f(y) + εδ(y-x)]^pφ(y)\, dy - \int [f(y)]^pφ(y)\, dy\right] $$ $$ =...- Bishamonten
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- Derivative Functional Functional derivative
- Replies: 7
- Forum: Advanced Physics Homework Help
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A Taylor series expansion of functional
I'm studying QFT in the path integral formalism, and got stuck in deriving the Schwinger Dyson equation for a real free scalar field, L=½(∂φ)^2 - m^2 φ^2 in the equation, S[φ]=∫ d4x L[φ] ∫ Dφ e^{i S[φ]} φ(x1) φ(x2) = ∫ Dφ e^{i S[φ']} φ'(x1) φ'(x2) Particularly, it is in the Taylor series...- vishal.ng
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- Expansion Functional Functional derivative Path integral formulation Quantum field theory Series Series expansion Taylor Taylor expansion Taylor series
- Replies: 4
- Forum: High Energy, Nuclear, Particle Physics
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B How do we obtain a Taylor expansion of a non-linear functional?
Hi PF I try to understand how we get get a Taylor expansion of a non linear functional. I found this good paper here F maps functions to scalars. F[f] is defined. It has not scalars as arguments. I agree with A13 and A18. In another paper (in french) skip to page 9 the fisrt term is ##\int dx...- naima
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- Derivative Functional Functional derivative
- Replies: 3
- Forum: Linear and Abstract Algebra
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Chain rule / Taylor expansion / functional derivative
Homework Statement To show that ##\rho(p',s)>\rho(p',s') => (\frac{\partial\rho}{\partial s})_p\frac{ds}{dz}<0## where ##p=p(z)##, ##p'=p(z+dz)##, ##s'=s(z+dz)##, ##s=s(z)## Homework Equations I have no idea how to approach this. I'm thinking functional derivatives, taylor expansions...- binbagsss
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- Chain Chain rule Derivative Expansion Functional Functional derivative Taylor Taylor expansion
- Replies: 1
- Forum: Calculus and Beyond Homework Help
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What is the solution for the attached equation?
Good afternoon, i was just wondering if this equation is possibly solvable where I(z) is a function of z. The equation is: I(z)=cosh(1/2 ∫I(z)dz) I know it looks stupid but is it possible? How would you approach this problem? Thank you.- eahaidar
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- Function Functional derivative Hyperbolic functions Integral Integral calculus Transcendental equation
- Replies: 4
- Forum: General Math
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Second functional derivative of fermion action
Homework Statement [/B] Consider the following action: $$\begin{align}S = \int \mathrm{d}^4 z \; \bar\psi_i(z) \, (\mathrm{i} {\not{\!\partial}} - m)_{ij} \, \psi_j(z)\end{align}$$ where ##\psi_i## is a Dirac spinor with Dirac index ##i## (summation convention for repeated indices). Now I would...- Ravendark
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- Derivative Fermion Functional Functional derivative Grassmann
- Replies: 6
- Forum: Advanced Physics Homework Help
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Functional Derivative: Evaluating & Understanding
In my textbook (see attached picture) there appears a functional derivative, but I honestly don't know how to evaluate a quantity like this. What should I do? I have tried to google but all I could find was how to take functional derivatives, where polynomials appeared under the integral, while... -
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Functional derivative of normal function
I can't convince myself whether the following functional derivative is trivial or not: ##\frac \delta {\delta \psi(x)} \big[ \partial_x \psi(x)\big],## where ##\partial_x## is a standard derivative with respect to ##x##. One could argue that ## \partial_x \psi(x) = \int dx' [\partial_{x'}... -
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Partial or Regular Derivative for Functional Derivative Stationary Value of 0?
Hi, I have a question about a functional derivative. When determining the condition that the functional derivative have a stationary value of 0, do I use a partial derivative or a regular derivative? I would really appreciate the help. Thank you! David- delve
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- Derivative Functional Functional derivative
- Replies: 2
- Forum: Topology and Analysis
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Mastering Functional Derivatives in Quantum Field Theory
Alright, so I feel kind of dumb...but: I have been working on some QFT material, specifically derivation of Feynman rules for some more simple models ( \phi^{4} for example), and I have been seriously failing with functional derivatives. Every time I try to use the definition I mess up...- Elwin.Martin
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- Derivative Functional Functional derivative
- Replies: 2
- Forum: Quantum Physics
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What is the proof for the functional derivative formula in DFT?
Hi, in their book ''Density-Functional Theory of Atoms and Molecules'' Parr and Yang state in Appendix A, Formula (A.33) If F ist a functional that depends on a parameter \lambda, that is F[f(x,\lambda)] then: \frac{\partial F}{\partial \lambda} = \int \frac{\delta F}{\delta f(x)}... -
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A simple functional derivative
Hi! I am doing some numerical calculations recently. I need to calculate the functional derivative. eg. functional : n(\rho)=\int dr'r'\rho(r')f(r,r') it need to calculate: \frac{\delta n(r)}{\delta\rho(r')} I think the...- sprik
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- Derivative Functional Functional derivative
- Replies: 1
- Forum: General Math
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What is meant by functional derivative?
What is meant by functional derivative? Thanks in well advance.- saravanan13
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- Derivative Functional Functional derivative
- Replies: 3
- Forum: Calculus
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Functional derivative of connection with respect to metric
I cannot work out the following functional derivative: \frac{\delta}{\delta g_{\mu\nu}} \int d^4 x f^a_{\phantom{a}b} \nabla_a h^b Where f is a tensor density f= \sqrt{\det g} \tilde{f} ( \tilde{f} is an ordinary tensor) and should be consider as independent of g. In my opinion this is not...- paweld
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- Connection Derivative Functional Functional derivative Metric
- Replies: 6
- Forum: Special and General Relativity
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Proving Functional Derivative for Current Research - Alice
For my current research, I need to prove the following: \int_0^1 \frac{dC(q(x) + k'(q'(x) - q(x)))}{dk'}\,dk' = \int_0^1 \int_L^U p(q(x) + k(q'(x) - q(x)))(q'(x)-q(x)) dx dk where C(q(x)) = \int_0^1 \int_L^U p(kq(x)) q(x)\,dx\,dk Here's what I've tried using the definition of functional...- alicexigao
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- Derivative Functional Functional derivative
- Replies: 1
- Forum: Calculus
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Functional Derivative: Computing the d'Alembert Solution
In the literature (Ryder, path-integrals) I have found the following relation for the functional derivative with respect to a real scalar field \phi(x) : i \dfrac{\delta}{\delta \phi(x)} e^{-i \int \mathrm{d}^{4} x \frac{1}{2} \phi(x) ( \square + m^2 ) \phi(x)} = ( \square + m^2 ) \phi(x)...- parton
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- Derivative Functional Functional derivative
- Replies: 4
- Forum: Advanced Physics Homework Help
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Chain rule with functional derivative
Given that F = \int{f[h(s),s]ds} does \frac{\partial}{\partial h}ln(F)=\frac{1}{F}\frac{\delta F}{\delta h}=\frac{1}{F}\frac{\partial f}{\partial h} ? -
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Adjoint of functional derivative in superspace
In the space of Riemannian metrics Riem(M), over a compact 3-manifold without boundary M, we have a pointwise (which means here "for each metric g") inner product, defined, for metric velocities k^1_{ab},k^2_{cd} (which are just symmetric two-covariant tensors over M)...- HenryGomes
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- Derivative Functional Functional derivative
- Replies: 1
- Forum: Special and General Relativity
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Chain rule with functional derivative
This is supposedly the chain rule with functional derivative: \frac{\delta F}{\delta\psi(x)} = \int dy\; \frac{\delta F}{\delta\phi(y)}\frac{\delta\phi(y)}{\delta\psi(x)} I have difficulty understanding what everything in this identity means. The functional derivative is usually a derivative... -
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Functional derivative: chain rule
Hmm, I've been working with functional derivatives lately, and some things aren't particularly clear. I took the definition Wikipedia gives, but since I know little of distribution theory I don't fully get it all (I just read the bracket thing as a function inner product :)). Anyway, I tried...- CompuChip
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- Chain Chain rule Derivative Functional Functional derivative
- Replies: 7
- Forum: General Math