10 m dive. Time and horizontal displacement is known.

AI Thread Summary
The diver jumps from a 10 m platform, spending 2.3 seconds in the air and achieving a horizontal displacement of 4 m. The initial velocity (Vo) and angle (θ) can be calculated using the equations for horizontal and vertical motion. By setting up the equations, it is determined that Vo cos(θ) equals approximately 1.74 m/s and Vo sin(θ) equals about 7.13 m/s. This leads to a tangent ratio of θ being 4.1, resulting in an angle of approximately 75.5 degrees and an initial velocity of about 7.37 m/s. The calculations provide a clear understanding of the diver's motion parameters.
andorini
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Homework Statement


A diver jumps from a 10 m platform.Time in air is 2.3 s. Horisontal displacement is 4 m.
What is the divers initial velocity and angle?

Homework Equations


No idea :'(

The Attempt at a Solution


No idea :'(
 
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suppossed initial velocity as Vo and angle is θ. horisontal displacement = Vo cosθ t. so that Vo cosθ = 40/23. vertical displacement = Vo sinθt - 1/2 g t2. so that Vo sinθ = 329/46 (for g=10). by comparison with Vo sin θ and Vo cos θ obtained tan θ = 4,1. in such a way that θ = tan-1 4,1. and Vo = 7,37.
 

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