11th gr. chem (composition of a hydrate)

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The discussion centers on a lab analysis of the composition of a hydrate, specifically copper(II) sulfate pentahydrate (CuSO4·5H2O). The user is confused about their calculations, particularly regarding the percentage of water lost during the transition to anhydrous copper(II) sulfate and the empirical formula derived from their data. They initially calculated that 36% of water was removed but were advised to verify their method and ensure they are solving for the correct variable 'X' in the hydrate formula. The importance of using raw data for accurate calculations was emphasized, indicating that assumptions could lead to errors. Clarification on these points is needed to ensure accurate lab results.
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i might get confusing cause i don't understand this very much
but here is the copy of my lab i need help with #1 & 6 of the POST-ALAYSIS
here is the word doc. of my lab
http://courses.digitaldapp.org/documents/Inquiry Lab - Experiment 03 - Composition of a Hydrate.doc


btw.
5 grams of copper II sulfate was used
when it became an anyhride it had a mass of 0.15g


i know i made a mistake somewhere in my lab and i was wondering if you tell where my mistake is and what i should do. i would highly appreciate it.

so i know...
CuSO4 . 5H2O
molar weight is 249.69g


by itself is
CuSO4 = 159.61g
5H2O= 90.81

so i took the
mass of the water/total mass of hydrate x100= 36% of H2O removed in anhydrous copper (II) sulfate.

am i correct?
this is where i got confused...
-determine the # of moles of water present in each mole of hydrous copper (II) sulfate.
so what i did was:
5H2O

H10= 11%=11/1.0079=10.91=2
O5=88%=88/15.9994=5.5=1
is this the correct Empirical formula?
2H10O5 & can be simplified to 2H2O

so now what do i use to find the amount of moles of water present?
 
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monica_e826 said:
i might get confusing cause i don't understand this very much
but here is the copy of my lab i need help with #1 & 6 of the POST-ALAYSIS
here is the word doc. of my lab
http://courses.digitaldapp.org/documents/Inquiry Lab - Experiment 03 - Composition of a Hydrate.doc


btw.
5 grams of copper II sulfate was used
when it became an anyhride it had a mass of 0.15g

Are you sure you got that right? I assume that "it had a mass of..." means that the anhydride had a mass of... Is that right?


i know i made a mistake somewhere in my lab and i was wondering if you tell where my mistake is and what i should do. i would highly appreciate it.

so i know...
CuSO4 . 5H2O
molar weight is 249.69g


by itself is
CuSO4 = 159.61g
5H2O= 90.81

Good so far...

so i took the
mass of the water/total mass of hydrate x100= 36% of H2O removed in anhydrous copper (II) sulfate.

am i correct?
this is where i got confused...
-determine the # of moles of water present in each mole of hydrous copper (II) sulfate.
Here is where you strayed off course. The formula for your unknown hydrate is CuSO4 . XH2O. You need to solve for 'X', not assume that it is 5 and do some math without using any of the data you collected.

Show us the raw data you collected.
 
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