Why Does Coulomb's Unit Measurement Include Seconds?

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A coulomb is defined as the total charge carried by a current of one Ampere over one second, leading to its unit being Amperes seconds rather than Amperes per second. The mathematical relationship I = dQ/dt shows that charge (Q) is the integral of current (I) over time (t), resulting in units of Amperes multiplied by seconds. This distinction emphasizes that a coulomb represents a total amount of charge, not a rate, similar to how energy is defined as power multiplied by time. Therefore, after two seconds, the total charge would be two coulombs. Understanding this difference clarifies the unit measurement of coulombs.
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If a coulumb is defined as the amount of charge carried by a current of one Ampere in a second, why is its units Amperes seconds and not Amperes per seconds?
 
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I=\frac{dQ}{dt} by definition and so Q = \int I\;dt which has a unit of (amperes x seconds)
seems obvious to me, do I understand your question correctly?
 
Yes, I see how it works mathematically. But I just thought "the amount of charge carried by a current of one Ampere in a second" was similar to the amount of charge carried by a current of one Ampere per second" so it would have units of Amperes/S
 
No because a coulomb is a total amount of charge not a rate, so after 2 seconds you have 2 coulombs.
 
yeah, another example Energy = Power x time
and Energy is not a rate, while Power is. so amount of charge is like "energy" in this analogy
 

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