1st order, non linear, homogeneous, ODE

Schmoozer
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Homework Statement



"Solve the following ODE's:"
"3u+(u+x)u'=0"

This is our first weeks homework and he went this through this so quickly in class.

Homework Equations



None. x and u are both variables.

The Attempt at a Solution


I know it is homogeneous and non linear. I tried v-substitution and just couldn't get a v to fit. Do i need to use the method of integration factor?

Thanks guys!
 
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Schmoozer said:
I tried v-substitution and just couldn't get a v to fit.
Why doesn't this work? What do you understand by v-substitution?
 
Not much, I feel like I'm guessing... any suggestions what i should substitute?
 
Schmoozer said:

Homework Statement



"Solve the following ODE's:"
"3u+(u+x)u'=0"
Perhaps better to rewrite it as
u'= \frac{-3u}{u+x}= \frac{-3\frac{u}{x}}{\frac{u}{x}+ 1}

This is our first weeks homework and he went this through this so quickly in class.

Homework Equations



None. x and u are both variables.

The Attempt at a Solution


I know it is homogeneous and non linear. I tried v-substitution and just couldn't get a v to fit. Do i need to use the method of integration factor?

Thanks guys!
 
-(1/4)ln|(u/x)|=ln|x|+c ?

Thanks so much. This class is like diffy eq on steroids and wasn't very good at diffy eq.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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