MHB 2.6.284 AP calculus Exam Lamp and Shadow related rates

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The discussion revolves around solving a common AP Calculus problem involving lamp and shadow related rates. Participants express difficulty with the problem, noting that some examples are overly complex with multiple variables and steps. A specific challenge is to solve the problem efficiently, with a target time of under five minutes given a rate of change of the shadow. The conversation highlights the importance of setting up the correct ratios to simplify the problem. Overall, the thread emphasizes the need for clarity and efficiency in tackling related rates problems.
karush
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yes I know this is a very common problem but likewise many ways to solve it
View attachment 9488

ok I really have a hard time with these took me 2 hours to do this
looked at some examples but some had 3 variables and 10 steps
confusing to get the ratios set up... ok my take on it is here

see if you can solve it under 5 min
 
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given $\dfrac{dx}{dt}= 4 \text{ ft/sec}$

$\dfrac{15}{x+s} = \dfrac{6}{s} \implies s = \dfrac{2x}{3} \implies \dfrac{ds}{dt} = \dfrac{2}{3} \cdot \dfrac{dx}{dt} = \dfrac{8}{3} \text{ ft/sec}$