2.6.284 AP calculus Exam Lamp and Shadow related rates

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SUMMARY

The discussion focuses on solving a common related rates problem in AP Calculus, specifically involving lamp and shadow scenarios. The participant expresses difficulty in understanding the setup, particularly with problems that include multiple variables and lengthy steps. They challenge others to solve the problem efficiently, given the rate of change of the shadow length at 4 ft/sec. The emphasis is on simplifying the approach to achieve a solution in under five minutes.

PREREQUISITES
  • Understanding of related rates in calculus
  • Familiarity with differentiation techniques
  • Knowledge of geometric relationships in shadow problems
  • Ability to set up and solve equations involving rates of change
NEXT STEPS
  • Practice solving related rates problems using lamp and shadow scenarios
  • Review differentiation rules and their applications in real-world problems
  • Explore geometric principles related to similar triangles in shadow problems
  • Learn strategies for simplifying complex multi-variable problems in calculus
USEFUL FOR

AP Calculus students, educators teaching related rates, and anyone looking to improve their problem-solving skills in calculus applications.

karush
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yes I know this is a very common problem but likewise many ways to solve it
View attachment 9488

ok I really have a hard time with these took me 2 hours to do this
looked at some examples but some had 3 variables and 10 steps
confusing to get the ratios set up... ok my take on it is here

see if you can solve it under 5 min
 
Physics news on Phys.org
given $\dfrac{dx}{dt}= 4 \text{ ft/sec}$

$\dfrac{15}{x+s} = \dfrac{6}{s} \implies s = \dfrac{2x}{3} \implies \dfrac{ds}{dt} = \dfrac{2}{3} \cdot \dfrac{dx}{dt} = \dfrac{8}{3} \text{ ft/sec}$
 

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