Solving 2 Counting Problems: 9 Women, 6 Men & 25 Flags on 10 Poles

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In summary, the problem is asking how many ways 9 women and 6 men can be seated on 15 seats on a table without any men sitting next to each other. The solution involves finding the number of ways to place 9 women in 6 spaces, and then dividing by 6 to eliminate repeats. The second problem is asking how to place 25 unique flags in 10 numbered boxes, where the order of the flags in each box matters.
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ghostskwid
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Homework Statement


1. 9 women, 6 men are to be seated on a table with 15 seats, how many ways can you assign the seats if no two men are seated next to each other.?

2. How to place 25 unique flags on 10 numbered flagpole if order of the flags on a flagpole is relevant


Homework Equations





The Attempt at a Solution



1. So for one, I know that with 15 people you simply would do 15! then eliminate the cycling arrangements, or divide by 15 since ABCDEF is equal to FABCDE for 6 so you would divide by 6 to eliminate repeats. Not sure how to handle men sitting next to each other.

2. I'm not sure I understand this questions, it is worded verbatim as the instructor state it. If it's jut 10 flagpoles...it would just be 25! / 15! but...I think it might mean 10 flagpoles total and you can put flags on them in any order.

Thanks!
 
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  • #2
hi ghostskwid! :smile:
ghostskwid said:
1. 9 women, 6 men are to be seated on a table with 15 seats, how many ways can you assign the seats if no two men are seated next to each other.?

how many ways can you put 9 women into 6 spaces (with at least 1 woman in each space)? :wink:
2. How to place 25 unique flags on 10 numbered flagpole if order of the flags on a flagpole is relevant

they mean how to place 25 unique flags in 10 numbered boxes
 

What are the 2 counting problems?

The first counting problem involves 9 women and 6 men, and the second counting problem involves 25 flags on 10 poles.

How many different ways can the 9 women and 6 men be arranged?

The number of different ways the 9 women and 6 men can be arranged is 15!/(9!6!) = 5005.

How many different ways can the 25 flags be arranged on the 10 poles?

The number of different ways the 25 flags can be arranged on the 10 poles is 10^25 = 9.765625e+24.

What is the total number of possible combinations for both counting problems?

The total number of possible combinations for both counting problems is the product of the number of combinations for each problem, which is 5005 * 9.765625e+24 = 4.8828125e+28.

How can these counting problems be solved using mathematical formulas?

The first counting problem can be solved using the formula n!/r!(n-r)!, where n is the total number of objects and r is the number of objects being selected. The second counting problem can be solved using the formula n^r, where n is the number of poles and r is the number of flags to be placed on each pole.

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