2 Dimensional Motion: Net force at an angle

Thread starter ayans2495
Start date Aug 22, 2021
Tags

Accelaration Angle Force Motion Motion in 1d Motion in 2d Net Net force Newton's second law

Click For Summary

To determine the acceleration in two-dimensional motion, the horizontal component of the net force is divided by the mass. The calculated value of 0.4 m s^-2 is confirmed as correct. The discussion emphasizes the importance of resolving forces into components for accurate calculations. Overall, the method used to find acceleration from net force is validated. This approach is essential for understanding two-dimensional motion dynamics.

Aug 22, 2021

ayans2495

Homework Statement: A mass of 40 kg, sitting on a smooth surface, is acted on by a force of 18 N eastward inclined upward at 30 degrees. Find the acceleration.

Relevant Equations: F=ma

Physics news on Phys.org

Aug 22, 2021

ayans2495

My solution was to find the horizontal component of the net force and divide that by the mass. Am I right?

Aug 22, 2021

Lnewqban

Homework Helper

Gold Member

Your solution is correct.

Aug 22, 2021

ayans2495

Lnewqban said:

Your solution is correct.

Thank you for your reply. I also got a value of 0.4 m s^-2, is that also correct?

Aug 22, 2021

Lnewqban

Homework Helper

Gold Member

Yes, it is.

Thread 'Chain falling out of a horizontal tube onto a table'

My attempt: Initial total M.E = PE of hanging part + PE of part of chain in the tube. I've considered the table as to be at zero of PE. PE of hanging part = ##\frac{1}{2} \frac{m}{l}gh^{2}##. PE of part in the tube = ##\frac{m}{l}(l - h)gh##. Final ME = ##\frac{1}{2}\frac{m}{l}gh^{2}## + ##\frac{1}{2}\frac{m}{l}hv^{2}##. Since Initial ME = Final ME. Therefore, ##\frac{1}{2}\frac{m}{l}hv^{2}## = ##\frac{m}{l}(l-h)gh##. Solving this gives: ## v = \sqrt{2g(l-h)}##. But the answer in the book...

View full post »