2 dimensional projectile motion

AI Thread Summary
To determine the minimum speed required for a stunt driver to jump over 10 parked cars, the horizontal distance is 80 ft and the vertical distance is 6 ft. Using the equations for projectile motion, the horizontal component of velocity is calculated as 80/cos(45), resulting in approximately 113 ft/s. The vertical component is derived from 6/sin(45), yielding about 8.5 ft/s. It is suggested to consult Kinematic Equations for a deeper understanding of the problem. The calculations indicate the necessary speed for a successful jump.
christy77
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Homework Statement



A stunt driver wants to make his car jump over 10 cars parked side by side below a horizontal ramp. if the horizontal distance is 80 ft and vertical distance is 6 ft., what is the minimum speed must the driver drive off the ramp?

Homework Equations



vx=v°*cos(θ)
v°y=v°sinθ


The Attempt at a Solution


80/cos45=113
6/sin45=8.5
 
Last edited:
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Are you going to attempt this problem?
 


i did
 
You should look up Kinematic Equations in your book or with google.
 

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