2 Masses connected by a spring

  • Thread starter Thread starter glover261
  • Start date Start date
  • Tags Tags
    Spring
AI Thread Summary
To find the acceleration of a system with two masses connected by a spring, it's essential to draw free body diagrams for each mass and account for all forces, including the spring's force. The acceleration of the larger mass, calculated as 5 m/s², may be incorrect if the spring's restoring force is not considered. The downward forces are irrelevant in a frictionless horizontal setup, where only horizontal forces affect acceleration. The proper approach involves including the spring's force in the calculations rather than simply adding the accelerations of each mass. Understanding the dynamics of coupled masses is crucial for accurate results in such systems.
glover261
Messages
8
Reaction score
0
Hello I am trying to find the acceleration of a system that has 2 masses, m1 and m2 connected via a spring with a spring constant of k with a force of F applied to the larger mass in the direction that stretches the spring.
 
Physics news on Phys.org
Very good. How are you going about it?
ie. did you try Newton's method of drawing free body diagrams for each mass?
 
Simon Bridge said:
Very good. How are you going about it?
ie. did you try Newton's method of drawing free body diagrams for each mass?

Yeah I found the forces acting downwards but I think they are irrelevant because all the acceleration for the system would be in the sideways direction. I found that the acceleration of the 3kg (larger) mass is 15/3= 5ms/^2, but I'm not sure if this is correct because wouldn't the spring be pulling back on it and therefore lowering its acceleration? I am not really sure how to find the acceleration of the whole system, do I try find the acceleration of each mass and add them? How do I do that when a spring is involved?
 
glover261 said:
Yeah I found the forces acting downwards but I think they are irrelevant because all the acceleration for the system would be in the sideways direction.
I think you may have left out some important information in your problem statement:
I was imagining both masses on a level frictionless surface with one to the left of the other ... in that situation the sum of the vertical (acting downwards) forces is zero.

I found that the acceleration of the 3kg (larger) mass is 15/3= 5ms/^2,...
This cannot follow from post #1 because you have not given any values for m1, m2 or F. It is unlikely to be correct because you have not accounted for the force from the spring.

...but I'm not sure if this is correct because wouldn't the spring be pulling back on it and therefore lowering its acceleration?
Yes.

I am not really sure how to find the acceleration of the whole system, do I try find the acceleration of each mass and add them?
This is not how you would normally treat the accelerations of coupled masses is it?

How do I do that when a spring is involved?
You include the force due to the spring in the free body diagram.
Think how you would do this problem if the spring were replaced by a string?
 
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Some physics textbook writer told me that Newton's first law applies only on bodies that feel no interactions at all. He said that if a body is on rest or moves in constant velocity, there is no external force acting on it. But I have heard another form of the law that says the net force acting on a body must be zero. This means there is interactions involved after all. So which one is correct?
Thread 'Beam on an inclined plane'
Hello! I have a question regarding a beam on an inclined plane. I was considering a beam resting on two supports attached to an inclined plane. I was almost sure that the lower support must be more loaded. My imagination about this problem is shown in the picture below. Here is how I wrote the condition of equilibrium forces: $$ \begin{cases} F_{g\parallel}=F_{t1}+F_{t2}, \\ F_{g\perp}=F_{r1}+F_{r2} \end{cases}. $$ On the other hand...
Back
Top