2 masses connected by spring, one is pulled, how much does the spring stretch?

In summary, the stretch of a spring connecting two masses can be calculated using Hooke's Law, which states that the force exerted by a spring is proportional to its displacement from the equilibrium position. When one mass is pulled, it creates tension in the spring, leading to a stretch that depends on the spring constant and the force applied. The resulting stretch can be determined by the formula \( F = k \cdot x \), where \( F \) is the applied force, \( k \) is the spring constant, and \( x \) is the stretch of the spring. The system's dynamics, including the masses and any friction, also influence the final displacement.
  • #1
Obliv
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Homework Statement
The masses are connected by a massless spring on a frictionless surface. One of the masses is pulled by a force F, how much does the spring stretch if at all?
Relevant Equations
F = ma, F = -kx
View attachment 332091
Hi, I am having trouble with this problem. I'm thinking the solution is this but I'm not sure. Fnet=m1a+m2aFnet=m1a+m2a , m1a=kxm1a=kx, m2a=Fkxm2a=F−kx so x=m1ak=−(m2aF)kx=m1ak=−(m2a−F)k
 
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  • #2
nvm
 
  • #3
So what answer did you finally get? Does it reduce to what you would expect in the limiting cases ##m_1<<m_2## and ##m_1>>m_2##?
 
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  • #4
... I suggest first assuming that ##m_1## is so large that it doesn't move. That gives you an easier problem to get you started.
 
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