2 refrigerators maintaining temperature

AI Thread Summary
When comparing two refrigerators set to the same thermostat temperature, one empty and one full of food, the full refrigerator may require slightly more energy to maintain temperature due to the presence of more matter that can absorb and radiate heat. However, once both refrigerators have reached the set temperature, the energy consumption primarily depends on external heat entering the fridge, which is independent of the contents if the door remains closed. The full fridge could draw more energy if frequently accessed, but this is a behavioral factor rather than a physical one. The discussion highlights that while the full fridge has more thermal mass, the key factor in energy usage after reaching the setpoint is the heat exchange with the environment. Ultimately, the energy required to maintain temperature is largely determined by external conditions rather than the amount of food inside.
redsrtturbo
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I can't go to sleep until I find an answer and I'm no student of physics so I was hoping for a little help.

If two refrigerators are at the same thermostat setting. One empty (assumed regular Earth air inside) and one full of food.

Both have already reached the temperature on the thermostat. Which will require more energy to maintain at the set temperature (not specified)?

I don't know what equations to use here or if my thoughts are even in the right direction but here goes:

It would take more energy to maintain the fridge full of food b/c it has more matter that is subject to reaching equilibrium and so the refrigerator has to actively fight this and costs more energy than the fridge full of air.

Hit or Miss?
 
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Why would a refrigerator require more energy to maintain the contents' temperature after reaching the setpoint? Make a list of the inefficiencies of the system. Do any of them involve the contents (air or solid)?
 
They would be set in the real world.

One would be full (fluids and solids can be assumed), and the other just plain air.

I assume they would still have to cool to remain at an arbitrarily set temperature. Which would have to cool more (use more energy) to keep the temperature inside at the predetermined level.
 
Again, we have to look at why the refrigerator has to keep running at all. Is it heat conduction through the walls, for example? This factor doesn't seem to depend on whether the refrigerator is full or empty.
 
They would be the same provided you didn't open the fridge (in that case the fridge with food would be cooler than the one with just air since the solid matter wouldn't disperse out the door).
 
ok- got the answer... the fridge would only have to run to maintain temp, kinda like when you hear them cycle on. I can't believe such a simple answer was so elusive.

Thanks, now I can get some sleep.
 
Well, there are more items in the full fridge that radiate energy, so would it actually require slightly more energy?
 
that's what I thought- since there was more matter in the fridge to transfer heat, it would heat up more and so need to be cooled more-
 
redsrtturbo said:
that's what I thought- since there was more matter in the fridge to transfer heat, it would heat up more and so need to be cooled more-
A refrigerator with food in it would draw more energy to keep it cool because people would be opening the door to get stuff to eat. If it was empty, no one would bother opening the door. But if this a physics and not a home economics question, that is not what is being asked.

Mapes is right. Since the food is already at the temperature set by the thermostat, the only thing which determines how much energy the refrigerator uses would be the amount of heat entering the refrigerator from the outside. That is independent of the amount of food in the fridge (if the door is kept closed).

AM
 
  • #10
Just to follow up on this. The refrigerator with food in it would require more energy to reach the temperature setting of the thermostat.

But, that is irrelevant to answering this question, since it asks about the energy used after it has reached the temperature setting.
 
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