2D Motion with a missle/engines

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SUMMARY

The discussion focuses on calculating the initial velocity of a spacecraft after two engines fire for 505 seconds, providing accelerations of ax = 5.10 m/s² and ay = 7.30 m/s. The final velocity components are given as vx = 3610 m/s and vy = 4928 m/s. The initial velocity in the x-direction is calculated as Vi = 1034.5 m/s, but the initial y-component was not computed correctly. The correct approach involves using the Pythagorean theorem to find the magnitude and applying the tangent function to determine the angle with respect to the +x axis, resulting in an angle of 55.06 degrees.

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On a spacecraft two engines fire for a time of 505 s. One gives the craft an acceleration in the x direction of ax = 5.10 m/s2, while the other produces an acceleration in the y direction of ay = 7.30 m/s2. At the end of the firing period, the craft has velocity components of vx = 3610 m/s and vy = 4928 m/s. Find the magnitude and direction of the initial velocity. Express the direction as an angle with respect to the +x axis.



Vf= Vi +at

tan O= opp/adj

3610 m/s = Vi + (5.1 x 505)

Vi= 1034.5 m/s

tan O= 7.3/ 5.1
O= 55.06 degrees


the answer was incorrrect and I have no idea what else to do
 
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You found the initial x component well enough but you didn't find the y component. You then need to find the magnitude (i.e. pythagoras) and then apply your tan formula to the initial speeds.
 

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