(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Two traffic signals are temporarily suspended from a cable as shown. Knowing that the signal at B weighs 300N. Determine the weight at signal C.

2. Relevant equations

Red arrows show lengths of cables and their components.

Answer is : W_c = 97.7N

3. The attempt at a solution

I started by drawing two free body diagrams. One for particle B and the other for particle C. They both share the cable BC, hence, they share the same tension, T_bc, right? So, I tried to solve for T_bc with the free body diagram of particle B resulting in the sum of the forces along x: -T_ab(3.6/3.9) + T_bc(3.4/3.42) =0

(Sigma = addition of forces) SigmaF_y: T_ab(1.5/3.9) + T_bc(.4/3.42) - 300 = 0

So, solving for T_bc I get 251 N. I then follow the same steps as above for particle C.

I get Sigma F_x: T_bc(3.4/3.42) + T_cd(2.4/2.5) = 0

Sigma F_y: T_bc(.4/3.42) + T_cd(.7/2.5) - W_c = 0

so far? when I plug in what I got for T_bc to the second eqns. I get a different answer for w_c than what i'm supposed to get. please help

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# Homework Help: 2D Particle Equilibrium

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