58th derivative of (1+x^3)^30 at x=0

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Homework Statement



find the 58th derivative of (1+x^3)^(30) at zero (The Answer is zero)

Homework Equations



The binomial series expansion
the maclaurin series (f^(n)(0)/n!)x^n

The Attempt at a Solution


So I expanded the given equation into the binomial series and at at the 19th term, I got 30(30-1)...(30-19+1)/57! * x^(57). But I don't get how that gets me any closer to the answer of zero.
 
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freshman2013 said:

Homework Statement



find the 58th derivative of (1+x^3)^(30) at zero (The Answer is zero)

Homework Equations



The binomial series expansion
the maclaurin series (f^(n)(0)/n!)x^n

The Attempt at a Solution


So I expanded the given equation into the binomial series and at at the 19th term, I got 30(30-1)...(30-19+1)/57! * x^(57). But I don't get how that gets me any closer to the answer of zero.

First just figure out what powers of x could have a nonzero 58th derivative at zero. Try a few.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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