A 9.0 killogram mass and a 3.0 kg mass are at rest on a frictionless

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A 9.0 kg mass and a 3.0 kg mass are initially at rest on a frictionless table, separated by a compressed spring. When the thread holding them together breaks, the 9.0 kg mass moves to the left at 2.0 m/s. The discussion reveals that the 3.0 kg mass will move in the opposite direction with a speed that is three times that of the 9.0 kg mass due to the difference in mass. Therefore, the velocity of the 3.0 kg mass is calculated to be 6.0 m/s. This conclusion is reached by applying the principles of momentum and acceleration in a frictionless environment.
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1. a 9.0 killogram mass and a 3.0 kg mass are at rest on a frictionless table. A massless spring is compressed between the masses, which are held together by a thread. The thread breaks and the 9.0 kg mass moves to the left with a velocity of 2.0 m/s. Find the velocity of the 3.0 kg mass.



2, m1v1+m2v2=(m1+m2)v3



3. 9(2)+3
18+0=12v3
v3=1.5m/s
this was my original attempt, but i realize it is not solving for the velocity of the 3.0kg mass but i don't know what else to do
 
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What does v3 mean? ehild
 


It stands for the final combined velocity but i am not sure if this equation is right for this problem.
 


No, it is not the final combined velocity. Read the problem: the final velocity of one mass is 2 m/s and you need to find the velocity of the other mass. So there is no combined final velocity. But what do you know about of the initial velocities? Do the masses move?

ehild
 


The masses are initially at rest and then they move in opposite directions
 


scbeturner said:
The masses are initially at rest and then they move in opposite directions

What is the momentum of the system then?

ehild
 


The force that moves the blocks after the thread breaks?
 


scbeturner said:
1. a 9.0 killogram mass and a 3.0 kg mass are at rest on a frictionless table. A massless spring is compressed between the masses, which are held together by a thread. The thread breaks and the 9.0 kg mass moves to the left with a velocity of 2.0 m/s. Find the velocity of the 3.0 kg mass.



2, m1v1+m2v2=(m1+m2)v3



3. 9(2)+3
18+0=12v3
v3=1.5m/s
this was my original attempt, but i realize it is not solving for the velocity of the 3.0kg mass but i don't know what else to do


The spring will apply the same sized force on each mass - but opposite in direction.

because the masses are 9kg and 3 kg, the effect of the force on the 3 kg mass will give 3 times the acceleration it causes to the 9kg mass.

That means the 3kg mass will be traveling at 3 times the speed of the 9kg mass at all times.

It sounds like after a while the masses have moved away from the spring. By then the 9 kg mass has accelerated to 2.0 m/s

What do you think that means for the 3 kg mass?
 


That its speed is 6m/s?
 
  • #10


scbeturner said:
That its speed is 6m/s?

That sounds entirely reasonable!
 
  • #11


Thank you so much!:)
 
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