A basic question about computing this derivative

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    Computing Derivative
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SUMMARY

The discussion centers on computing the derivative of an energy function E(I, J) defined as E(I,J) = ∫ CC_{p}(I,J) dp, where CC represents cross-correlation in image processing. The user, Anja, seeks clarification on whether the fundamental theorem of calculus allows for interchanging differentiation and integration in this context. The correct approach is confirmed to be ∂E(I,J)/∂v = ∫ ∂CC_{p}(I,J)/∂v dp, which clarifies the confusion regarding the derivative computation.

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anja.ende
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Hello,

This is my first post and I must emphasise that I do not have a science/maths training background and this might be a very basic question. I apologise if it is too basic to belong here.

I have a function defined as follows:

E(I,J) = [itex]\int CC_{p}(I,J)dp[/itex]

Just a little context, I am trying to do some image processing and E is some energy function (based on two images I and J) that needs to be maximised. CC is the cross correlation in an image neighbourhood p and the total energy is given by the summing up these local contributions.

Anyway, to maximise this function with respect to some variable 'v', I need to compute the derivative [itex]\frac{\partial E}{\partial v}[/itex]

My question is can I use the fundamental theorem of calculus and say that

[itex]\frac{\partial E}{\partial v} = \frac{\partial CC_{p}}{\partial v}[/itex]

I get a bit confused about this. I would really appreciate your help.

Thanks,
Anja
 
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You can interchange the order of the integration and differentiation and write:
[tex]\frac{\partial E(I,J)}{\partial v} = \frac{\partial}{\partial v}\int CC_p(I,J) dp = \int \frac{\partial CC_p(I,J)}{\partial v} dp[/tex]

But what you wrote is not correct. Does this help?
 
Yes, thank you!
 

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