A Burst of Colorful Spring Flowers

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http://img501.imageshack.us/img501/2654/z5jc.jpg"
thx.
 
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LasTSurvivoR said:
http://img501.imageshack.us/img501/2654/z5jc.jpg"
thx.

Looks like this belongs in the homework section.

Are you familiar with l'Hospital's rule?
 
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yup i knew it , but how can we use it here ? no 0 / 0 or everlasting / everlasting ?


/ Sry didnt saw homework sec
 
No worries, just use the homework section next time.

It's beena little while, but:
0^\infty
and
\infty^0
are also places that you can apply l'Hospitals rule.
Let's say we have two functions:
\lim_{x \rightarrow y} f(x) \rightarrow 0
and
\lim_{x \rightarrow y} g(x) \rightarrow \infty

Then
\lim_{x \rightarrow y} g(x)^{f(x)}=\lim_{x \rightarrow y} e^{f(x) \ln(g(x))}
And the exponent there is of the form:
0 \times \infty
 
You don't need to use l'hopital. Try pulling out the 7*8^n from inside the ().
 
NateTg i understand what you meant.Thanks.
 
But can't solve that : e ^ [ 2 / n . ln ( 5^n + 7.8^n ) ]

What should i do e ^ ( fx . gx ) now ?
 
Well the limit of the exponent is the exponent of the limit, but you're better off using shmoe's technique.
 
The first thing that jumps into my head is that the limit, if you remove the 5^n, is simply 7.8^(n*2/n) = 60.84. So, since we've ignored adding 5^n before rooting, the answer must be at least 60.84.

There's only one answer that satisfies that, clearly demonstrating why I love multiple choice tests so much.
 
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  • #10
I think that's supposed to be 7*8^n, otherwise none of the choices are correct.
 
  • #11
n's going to infinity right? Easy way is piecewise. 7*8^n >> 5^n as n => infinity, so that term can be neglected (basically same is dividing out the 7*8^n, just slightly quicker and less rigorous). You get 7^(2/n)*(8^n)^(2/n) => 8^2 = 64.
 
  • #12
I don't understand the question...I don't see any lim (x->something)

Do you mean maximum value? or the limit as x approaches infinity?

(5^2n + 5^n * 14 * 8^n + 49 * 8 ^2n) under a n-th radical...

I won't lie i don't know but my TI-84 does :D
 
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