Lets look at this from a different direction. Capacitance and inductance are mathematically... weird. They are differential equations and they hurt to look at. But I think it will help if you stick with me for a second. Let's look at Capacative and Inducive Impedance (just a slightly more complex flavor of resistance).
Z
L = jwL
Z
C = -j/(wC)
Ok so that j is a complex number. We can think about it as a direction, or more accurately as a "unit vector." It means that it only plays with numbers that also have a j in them and has no impact on non complex numbers.
The w is a frequency, L is inductance, and C is capacitance. All of these are positive numbers.
OK so lest do something crazy. Let's assume that our frequency, inductance ans capacitance are all fixed numbers, and let's replace them with constants tomake it easier to look at.
K
L for all of our inductive junk ( K
L = wL) and
K
C for all of our capacitive junk ( K
C = 1/wC )
Our equations then become Z
L = j*K
L
Z
C = -j*K
C
Now remember that j is nothing more than a direction. You'll notice that our inductive junk is contributing the system in a positive direction and the capacitive junk is contributing to the system in a negative direction.
The result of this is, when you add them,
you will always end up with one specific impedance. It might be somewhere +j or it might be -j but you will always get one number (don't tell a mathematician I said that but for our purposes it's true).
So let's say your Z
L and Z
C are equal. you will end up at the 0 point on the j line. The is a special point at which resonance happens.
So now that we have the background out of the way, let me address your specific questions.
Landru said:
Is it fair to say that the reason you can't measure the capacitance of an inductor directly is because, unlike a capacitor by itself, an inductor has inductance and capacitance in parallel with one another?
I don't think you can really say this. The reason you cannot measure the paracitic capacitance directly is because they are not really separate things. You can only measure where your component is on the j axis. remember its only one number.
Its also not safe to say that the capacitors do not have parasitic inductance. In fact, if you increase the frequency enough, a capacitor will become an inductor (you will increase w enough that you cross the 0 point on the j axis)
Landru said:
Is the purpose of solving for capacitance from the inductance and resonant peak of a coil to effectively remove the parallel inductor from the equation, leaving only the capacitance to be observed?
This is just a math trick. You are not removing the capacitance or inductance. Remember these values are determined only by the geometry of the coil.
What your doing there is finding the frequency (w) at which the effect of the Inductance and capacitance cancel each other out. You are finding the 0 point on the j axis. You then set the Impedances equal to one another. and solve for C.
Z
L = Z
C
Skipping the details you will end up with this.
wiggle it around to solve for C
Now you know f, and L, you can solve for your parasitic capacitance.
I think the confusion is coming from the lumped element model. Remember circuit diagrams are only models. They are just tools and no tool is perfect. Even though the circuit might show parasitic capacitance as a separate component in the circuit, that is really just a work around to make the math correct. It's a fix for a model only includes ideal components.