B Is α-Decay the Same as Nuclear Fission? Understanding the Difference

Haynes Kwon
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Is α-decay same as nuclear fission?
What is the difference?
 
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Typically it is only called "fission" if the process creates two or three nuclei of similar size, but that is purely a naming convention. Cluster decays are somewhere between alpha decays and fission.
 
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No, fission is not alpha decay and alpha decay is generally not considered as fission althoughit technically is a splitting of a nucleus in several parts. Generally, fission usually refers to the splitting of a nucleus in such a way that there are at least two products that carry a significant fraction of the original mass.
 
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Thank you all. May I ask one more?
I don't see why this is not nuclear fusion.

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Same thing: Just a matter of convention what is called fusion and what is not. I guess you could call that fusion, although ##(\alpha, n)## would be a more conventional notation for the reaction.
 
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Thank you very much.
 
Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...
I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...

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