A double-slit (Young experiment) problem

AI Thread Summary
In Young's double-slit experiment, the problem involves determining the phase difference (Φ) for destructive interference at a point on the screen. Two potential solutions were derived: Φ = 2kπ - π/4 and Φ = 2kπ + 5π/4. The first solution arises from equating the sum of the wave functions to zero, while the second solution is based on the condition for destructive interference related to the path difference. The discussion emphasizes that the condition for destructive interference must hold true at all times, leading to the need for further analysis of the cosine term. Ultimately, the key takeaway is the importance of ensuring that the interference condition is satisfied consistently.
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Homework Statement



In Young's double-slit interference experiment with light of wavelength \lambda, two light waves come from the slits and are superposed at the point P on the screen. These waves have the following forms:

E1 = E0 sin(wt + π/4)
E2 = E0 sin(wt + Φ)

Find the possible values of Φ if we have destructive interference at the point P.

Homework Equations



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The Attempt at a Solution



I attempted the problem two different ways and I had two different results.

Φ = 2kπ - π/4
Φ = 2kπ + 5π/4

Help me out please.
 
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Can you show us how you got that?
 
Phase difference is Φ - π/4.

So d/λ = (Φ - π/4)/2π

d = (2k+1)/2 λ for destructive interference

So, (2k+1)/2 λ = (Φ - π/4)/2π λ

Φ = 2kπ + 5π/4

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The second way, I added 2 wave functions together and I equated the expression to zero.

I found Φ = 2kπ - π/4
 
How did you arrive at Φ = 2kπ - π/4?
 
Let's see. The sum of the two waves is:

E = 2E0 sin(wt + π/8 + Φ/2) cos(π/8 - Φ/2) = 0

That is satisfied when

wt + π/8 + Φ/2 = kπ

wt=2πft=2π, so we can drop it.

Φ = 2kπ - π/4
 
physicist10 said:
Let's see. The sum of the two waves is:

E = 2E0 sin(wt + π/8 + Φ/2) cos(π/8 - Φ/2) = 0

That is satisfied when

wt + π/8 + Φ/2 = kπ

wt=2πft=2π, so we can drop it.

Φ = 2kπ - π/4

The condition E=0 must be satisfied at ALL TIME for destructive pattern, and the bold line is not true at all time.
Find another condition :wink:
 
Hmm, thanks hikaru. How can I proceed? I have no idea.
 
What about cos(π/8 - Φ/2)?
 
Oh yes, I found it now. I must equate the cosine term (cos(π/8 - Φ/2)) to zero. But why exactly?
 
  • #10
Because of this: "The condition E=0 must be satisfied at ALL TIME for destructive pattern" :wink:
 
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