A Force and Potential-Energy Problem

  • Thread starter Thread starter student34
  • Start date Start date
  • Tags Tags
    Force
AI Thread Summary
A conservative force being zero with respect to position x does not imply that potential energy U must also be zero. It is possible to have potential energy without an active force acting towards equilibrium, as demonstrated by a ball resting at the top of a hill. In this scenario, the force is zero, but the potential energy is at a maximum. The relationship between force and potential energy indicates that a zero force results in no change in potential energy for small displacements. Thus, potential energy can exist independently of the presence of a force.
student34
Messages
639
Reaction score
21

Homework Statement



My book says that just because a conservative force is zero with respect to x, doesn't necessarily mean that the potential-energy U has to be zero.

How can it be possible to have potential energy without a force acting towards the equilibrium?

Homework Equations



Fx(x) = dU(x)/dx = 0

The Attempt at a Solution



Fx(x)*Δx = -U, so 0*Δx = 0
 
Physics news on Phys.org
As your DEs show, it only implies that the change in PE is vanishingly small for small changes in x. Consider e.g. a ball sitting on the top of a hill.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top