A general condition on polynomial roots

Click For Summary
SUMMARY

The discussion centers on the conditions for the roots of a polynomial of the form A_n w^n + A_{n-1} w^{n-1} k + A_{n-2} w^{n-2} k^2 + ... + A_1 k^n = 0 to be either real or have even imaginary parts. Key insights include the relationship between turning points and the existence of real roots, where a function must cross the x-axis between turning points of opposite signs. The conversation also touches on the need for clarity regarding the roles of A_n, w, and k in the polynomial setup.

PREREQUISITES
  • Understanding of polynomial functions and their roots
  • Knowledge of calculus, specifically derivatives and turning points
  • Familiarity with complex numbers and imaginary roots
  • Basic concepts of Galois theory
NEXT STEPS
  • Research the implications of turning points on polynomial roots
  • Study the relationship between derivatives and root behavior in polynomials
  • Explore Galois theory and its connection to polynomial solvability
  • Examine the properties of complex functions and their roots
USEFUL FOR

Mathematicians, students of algebra and calculus, and anyone interested in the behavior of polynomial roots and their relationships with complex numbers.

lunogled
Messages
2
Reaction score
0
Consider a polynomial of the following type:

A_n w^n + A_{n-1} w^{n-1}k + A_{n-2} w^{n-2} k^2 + ... + A_1 k^n =0

What are the general conditions on {A_i} in order for the roots w(k) to be EITHER real OR functions with even imaginary parts, Im[w[k]]=Im[w[-k]]?

I would be interested in whether anyone has ever worked on this problem, or if this problem was ever shown to be unsolvable (perhaps there is a trivial connection to, e.g., Galois theory I missed).

Thanks, and best
 
Physics news on Phys.org
Hey lunogled and welcome to the forums.

One way to look at this problem is in terms of the derivatives. If you order your turning points in order and you find that a pair of ordered points occurs on the same side of the x-axis, then you will have an imaginary root.

Think of it this way: if you have a real root, then the function will cross the x-axis at some point between the two-turning points and since one turning point will happen at a positive y value and another turning point will happen at a negative y value then if the function is continuous, it has to have a real root because it has to touch the x-axis and not only that, it will touch it only once due to some theorems in analysis/calculus but you can use an intuitive argument if you wish.

So easiest way to tell for a standard y = f(x) function, if you have this kind of condition, you should get an imaginary root if this happens, and to check this you need to solve the information for your first and possibly second derivatives (for inflection points) of your function.
 
I'm confused by your setup. Where do the A_n's live? Is w the indeterminate? If so, why do you have k's in there (i.e. why are you homogenizing)? If w(k) is a root, what does it mean for w(-k) to be a root? Is the k in w(k) a subscript or are you somehow viewing w as a function of k?

Please clarify...
 
morphism said:
I'm confused by your setup. Where do the A_n's live? Is w the indeterminate? If so, why do you have k's in there (i.e. why are you homogenizing)? If w(k) is a root, what does it mean for w(-k) to be a root? Is the k in w(k) a subscript or are you somehow viewing w as a function of k?

Please clarify...

A_{n} are numbers. w as a function of k is indeterminate, so if w(k) is a root, w(-k) is also a root, w is defined as a function of k
 

Similar threads

  • · Replies 0 ·
Replies
0
Views
2K
Replies
12
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K