A gun that fired charged particles

AI Thread Summary
A gun that fires charged particles accelerates a 5-μC charge through a potential difference of 50,000 V, with a mass of 0.025 kg. The relationship between electrical potential energy (EPE) and kinetic energy (KE) is used to find the speed of the particle. The calculation shows that EPE equals (1/2) x (5^-6 C) x (50,000 V) and KE equals (1/2) x (0.025 kg) x (v^2). The user calculated a speed of 3.16 m/s, while the teacher indicated the correct answer is 4.5 m/s, suggesting a potential error in the application of the formula. Clarification on the correct formula for EPE is sought to resolve the discrepancy.
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Homework Statement


A gun that fires charged particles accelerates a 5-μC charge from rest through a potential difference of 50,000 V. The particle has a mass of 0.025 kg. With what speed does it leave the gun?


Homework Equations


EPE = KE
(1/2)qV = (1/2)mv^2 , solve for v^2



The Attempt at a Solution


EPE = (1/2) x (5^-6 Coulombs) x (50,000 Volts)

KE = (1/2) x ( 0.025kg) x (v^2)

where the problem lies:
When i solve for velocity i get 3.16 m/s, however the answer my teacher gave to this problem was 4.5 m/s. Am i missing something here??
 
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Are you sure that the electrical potential energy is (1/2)qV?
 
ahhh...nothing like a good 'ole misprint on the formula sheet to trip you up. thanks for the insight!
 
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