- #1
AdamFiddler
- 6
- 0
While reading Lee Smolin's book "Three Roads to Quantum Gravity" in which he talks about the Bekenstein bound and a smallest fundamental unit of area, the following occurred to me:
Suppose there does exist such a smallest unit, call it A.
Then there exists a smallest volume, V(a).
A singularity (in the sense of a black-hole), by definition has infinite density.
By the definition of density and the above lower bound on volume of a region V(a), the singularity must have infinite mass.
What gives?
Adam
Suppose there does exist such a smallest unit, call it A.
Then there exists a smallest volume, V(a).
A singularity (in the sense of a black-hole), by definition has infinite density.
By the definition of density and the above lower bound on volume of a region V(a), the singularity must have infinite mass.
What gives?
Adam