- #1
zee3b
- 7
- 0
Guys I know how to solve the simple ones but this one has complex roots
I have to find the zero input response
(D-1)(D2+1)y(t)=(D2+2)f(t)
y(0)=4 y'(0)=3 y''(0)=3
D2= D square. Y' = first derivative Y''= secondI know the roots are +1, j and -j
But I don't know how to solve or use the j's and their identity
I maybe wrong. If it wasn't for the square inside the parenthesis I would be able to solve it.
Any help would be appreciated. (step by step so i can understand it better) once again I know the whole concept but not the j's
I have to find the zero input response
(D-1)(D2+1)y(t)=(D2+2)f(t)
y(0)=4 y'(0)=3 y''(0)=3
D2= D square. Y' = first derivative Y''= secondI know the roots are +1, j and -j
But I don't know how to solve or use the j's and their identity
I maybe wrong. If it wasn't for the square inside the parenthesis I would be able to solve it.
Any help would be appreciated. (step by step so i can understand it better) once again I know the whole concept but not the j's
