A matrix satisfies A^2 - 4A + 5I = 0, then n is even.

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Homework Statement



1) Let A be an n x n matrix with A^2 -4A +5I = 0. Show that n must be even.

2) Let A be an m x n matrix where m<n. Show that det(AT x A) = 0

The Attempt at a Solution



1) (A-2I)^2 +I=0

Not sure what to do after this though


Thanks in advance
 
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Hydroxide said:

Homework Statement



1) Let A be an n x n matrix with A^2 -4A +5I = 0. Show that n must be even.
An n x n matrix with real entries? If it can have complex entries, this isn't true. Anyways, what do you know about minimal polynomials and characteristic polynomials?
2) Let A be an m x n matrix where m<n. Show that det(A^T x A) = 0
What do you know about the relationships between rank, invertibility, and determinants.
1) (A-2I)^2 +I=0
Okay, that's not bad. So (A-2I)2 = -I. Compute the determinant of both sides.
 
Cheers I've got the first question now. Was easier than i thought.

I still can't do 2) though.

AKG said:
What do you know about the relationships between rank, invertibility, and determinants.

Could you explain further please?
 
What are the dimensions of the matrix ATA? What can you say about the rank of ATA?
 
AKG said:
What are the dimensions of the matrix ATA? What can you say about the rank of ATA?

ATA is n x n
We haven't covered ranks yet

I know that ATA can reduced so that it has one row of zero's hence det=0. But I don't know how to show it in general.
 
It may help to think of matrix multiplication with a vector as a linear combination of the columns of the matrix

i.e. For A\vec{c} = \vec{b}\\ b is a linear combination of the columns of A

And hence a matrix multiplication with a vector will produce a matrix whose columns are a linear combination of the columns of the first matrix.

i.e. For AB = C\\ C's columns are linear combinations of the columns of A

Sorry if the Latex is less than desirable, as you can see, I'm new here.
 
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