A more complicated question on lipid phase diagrams

rwooduk
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Homework Statement


fQFWSOB.jpg


Homework Equations


None.

The Attempt at a Solution


This is the final part of a past exam question. I've got through the first parts and can (thanks to a separate question I asked here) read the phase diagrams and find melting points etc. However now it's asking for "composition trajectories", "phase morphology" and "domain size and internal structure" and I'm completely lost.

I can work out the molar proportions and compostions by drawing a line down the diagram at 22% and figuring the ratio at 42 degrees. But I have no idea what to do for the above quoted terms.

Any guidance would really be appreciated, I'm completely at a loss how you would derive this information from the phase diagrams given.
 
on Phys.org
How do you expect the size of the domains to compare when you cool rapidly compared to when you cool slowly? (Think nucleation rate)

Chet
 
Chestermiller said:
How do you expect the size of the domains to compare when you cool rapidly compared to when you cool slowly? (Think nucleation rate)

Chet

Thanks for the reply. I (think I) understand that kinetics influence the rate of transformation, i.e there is an additional barrier for cooling rapidly:

QHKEOja.jpg


So domains will form slower. Or have I misinterpreted the graph?

thanks again
 
I think that if you cool rapidly, you will get a lot more nucleation sites, so that, in the end, there will be many more domains, but they will all be smaller.

Chet
 
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Chestermiller said:
I think that if you cool rapidly, you will get a lot more nucleation sites, so that, in the end, there will be many more domains, but they will all be smaller.

Chet

Hmm, that would seem logical. The only 2 slides we have to solve this problem (not coursework, a past exam paper I'm working through for revision) are these:

s7g90vE.jpg


vXfO0cu.jpg


Slide 2 says they will eventually merge into 2 domains, so when the the question asks "domain size and internal structure" won't it eventually be the same whatever the cooling rate?

Could you comment on whether you think the slides help with this question, because I've tried interpreting them but I'm still no closer to answering this question (especially giving 10 marks worth of description).
 
I really don't know enough about this to comment. My experience on this type of thing relates to my experience with semi-crystalline polymers. Wish I could help further.

Chet
 
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Chestermiller said:
I really don't know enough about this to comment. My experience on this type of thing relates to my experience with semi-crystalline polymers. Wish I could help further.

Chet

That's no problem at all, thank you for your input!
 

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