What is the correct radius of the plane's loop?

  • Thread starter Thread starter IGeekbot
  • Start date Start date
  • Tags Tags
    Loop
AI Thread Summary
The discussion centers on calculating the radius of a plane's loop based on the forces acting on a pilot. A pilot weighing 75 kg experiences no force against the seat belt at the top of the loop, with an airspeed of 120 m/s. One participant calculated the radius using the centripetal acceleration formula, arriving at approximately 1469.39 meters, while another suggested a much smaller radius of 19.36 meters using Newton's second law. The consensus leans towards the larger radius being more plausible, as a loop of 19.36 meters is deemed unrealistic for an airplane. The correct approach confirms that gravitational force equals centrifugal force at the loop's apex, supporting the larger radius calculation.
IGeekbot
Messages
24
Reaction score
0
A pilot goes into a loop...

A 75 kg pilot goes into a loop. At the top of the loop, where the plane is completely upside down for an instant, the pilot hangs freely in the seat and does not push against the seat belt. The airspeed indicator reads 120m/s. What is the radius of the planes loop?


I did Ac=v^2/r

substitute 9.8 for ac and 120 for v, so...

9.8=120^2/r

and when you do that, the radius is 1469.39 m.


My friend disagrees and says the loop should only be 19.36 meters. He used F=ma, then put that into the equation, to get 19.36.


Can someone say who did it right?
 
Physics news on Phys.org
First of all. Which answer is more plausible. Surely I don't see an airplane make a loop with a radius of 19.36 meters.

But more rigorously. The gravitational force on the pilot equals the centrifugal force, since he doesn't push against the seat. So you're right.
 
Thank you, and yes, I had thought of the airplane making a 19m loop. Not going to happen.
 
You could still use F = ma, I don't know why you would, but you'd just you'd have to use it properly.

F = ma
F = \frac{mv^2}{R}
mg = \frac{mv^2}{R}
g = \frac{v^2}{R}
9.8 = \frac{120^2}{R}
...
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Correct statement about a reservoir with an outlet pipe'
The answer to this question is statements (ii) and (iv) are correct. (i) This is FALSE because the speed of water in the tap is greater than speed at the water surface (ii) I don't even understand this statement. What does the "seal" part have to do with water flowing out? Won't the water still flow out through the tap until the tank is empty whether the reservoir is sealed or not? (iii) In my opinion, this statement would be correct. Increasing the gravitational potential energy of the...
Thread 'A bead-mass oscillatory system problem'
I can't figure out how to find the velocity of the particle at 37 degrees. Basically the bead moves with velocity towards right let's call it v1. The particle moves with some velocity v2. In frame of the bead, the particle is performing circular motion. So v of particle wrt bead would be perpendicular to the string. But how would I find the velocity of particle in ground frame? I tried using vectors to figure it out and the angle is coming out to be extremely long. One equation is by work...
Back
Top