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A problem concerning logic

  1. Jan 12, 2008 #1
    Sorry if my title wasn't the best, dosen't know the english termonolgy

    Anyway i get diffrent result based on how i solve "pvq->r" the result vary if i solve this as (pVq)->r or pV(q->r).

    You can see me trying to solve this in the picture which i have attaced, below

    http://img183.imageshack.us/img183/2387/dscf0462ho0.jpg [Broken]

    Thank you for your time
     
    Last edited by a moderator: May 3, 2017
  2. jcsd
  3. Jan 12, 2008 #2

    HallsofIvy

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    Yes, you should- those have different meanings: (pvq)-> r means "if either p or q is true, then r is true." pv(q->r) means "either p is true or if q is true then r is true". The "precedence" rules for symbolic logic say that "and", v, takes precedence of "implication, ->, just as in arithmetic multiplication takes precedence of over multiplication takes precedence over addition: ab+ c means (ab)+ c. pvq->r, without parentheses, means (pvq)-> r.
     
    Last edited by a moderator: May 3, 2017
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