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A problem in differential equation

  1. Nov 17, 2011 #1
  2. jcsd
  3. Nov 17, 2011 #2

    lurflurf

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    by the chain rule
    [tex]\frac{d}{dx}=\frac{\partial}{\partial x}+\frac{dy}{dx}\frac{\partial}{\partial y}[/tex]
     
  4. Nov 17, 2011 #3
    What to do next.........
     
  5. Nov 17, 2011 #4

    lurflurf

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    [tex]\frac{d^2 y}{dx^2}=\frac{df}{dx}=\frac{\partial f}{\partial x}+f \frac{\partial f}{\partial y}[/tex]

    the values of f and its first order partials are known from the problem statement
     
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