What is the speed of the ball after bouncing off an elastic surface?

  • Thread starter Thread starter emc2_akshay
  • Start date Start date
AI Thread Summary
In an elastic collision, the speed of the ball after bouncing off a truck can be determined by considering the truck as an inertial reference frame. Since the truck's mass is significantly greater than the ball's, its speed remains effectively unchanged during the collision. The ball's incoming speed, as observed from the truck, is equal to the truck's speed minus the ball's throwing speed. After the collision, the ball's outgoing speed is the same as its incoming speed but in the opposite direction. Finally, to find the ball's speed after the bounce, add the truck's speed to the outgoing speed of the ball.
emc2_akshay
Messages
1
Reaction score
0
Excuse me, but will anyone of u be kind enough to help me with this quetion----
Q.==== A truck is moving towards you with a velocity v. You throw a ball at it with velocity x, which bounces of elastically after hittin hthe truck. What is the speed of the ball now?
 
Physics news on Phys.org
Since no masses are given, this is a conceptiual, not mathematical question. The answer is very simple if you understand a few concepts.

First there is an assumption: the mass of the truck is so much greater than the mass of the ball that the speed of the truck effectively does not change during the collision. So, that means you can "observe" this collision from the point of view of the truck (it's an "inertial reference frame). The elastic collision form the truck's POV, is just like the ball bouncing (perfectly elastically) off a stationary wall.

What is the incoming speed of the ball as seen by the truck? What is the outgoing speed of the ball as seen by the truck? Add to that last speed, the speed of the truck's frame of reference.
 
No, I really do not know to play such note :smile: :smile: :smile: :smile: :smile:
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...

Similar threads

Back
Top