A question on undetermined coefficients

shemer77
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Homework Statement


http://gyazo.com/6c440aa92106f729639c91f6d59dcd89


The Attempt at a Solution


My question is why is yp = At^3+Bt^2 +Ct. The reason I ask that is because is see t^2+2t so why wouldn't it be yp=At^2 +Bt +c?
 
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shemer77 said:

Homework Statement


http://gyazo.com/6c440aa92106f729639c91f6d59dcd89

The Attempt at a Solution


My question is why is yp = At^3+Bt^2 +Ct. The reason I ask that is because is see t^2+2t so why wouldn't it be yp=At^2 +Bt +c?
attachment.php?attachmentid=48917&stc=1&d=1341594524.png


Because (D3 + 4D)( At3+Bt2 +Ct) = 12At2 + 8Bt + 6A + 4C .

Whereas, (D3 + 4D)( At2+Bt+C) = 8At + 4B, which is not a quadratic.

.
 

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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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