A question regarding Fourier transform in electron microscop

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SUMMARY

The discussion focuses on calculating the finest detail obtainable from the Fourier transform of a micrograph captured at a magnification of 43,000x using a DE-20 digital camera. The camera features a pixel size of 6.4 μm and a frame size of 5120 × 3840 pixels. The smallest frequency in the image is determined by the inverse of the image size (1/L), where L is the image dimensions. The spacing between frequencies in the Fourier transform is also defined as 1/L, emphasizing the relationship between image size and frequency resolution.

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I have recorded a micrograph of a 2-D array at a magnification of 43,000x on my DE-20 digital camera, which has a 6.4 μm pixel size and a frame size of 5120 × 3840 pixels. This magnification is correct at the position of the camera. I then compute the Fourier transform of the image. What is the spacing of the finest detail (highest resolution Fourier Coefficient) that I can hope to obtain in the computed transform, with respect to the actual particle itself in the specimen plane? What is the spacing between points in the computed Fourier transform (with respect to the original object, i.e. the crystal)?

I feel confused about the Fourier transform. So any help will be welcome. Thanks in advance!
 
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Not sure this adresses your question, but the Fourier transform is not a function on ordinary space, it is a function on the space of (spatial) frequencies. The smallest frequency present in your image is 1/L where L is the size of your image (where "1" is some constant depending on conventions). The spacing between frequencies is also 1/L.
 
I suggest that you look up topics about discrete Fourier transform, there you can find how to calculate the finest possible resolution for the calculate object.
 

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