A screen for detecting electrons

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  • #26
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So in that case would it be 2.855 E6?
 
  • #27
SammyS
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So in that case would it be 2.855 E6?
No.

How much does the (negative) acceleration decrease the vertical component of the velocity in a time of 5.47×10-7 seconds?
 
  • #28
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well if acceleration is the change in velocity/ time then would it be -9.39E11= 2.855 E6- vy/ 5.47×10-7 ?
 
  • #29
SammyS
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well if acceleration is the change in velocity/ time then would it be -9.39E11= (2.855 E6- vy)/ 5.47×10-7 ?
If you use parentheses correctly, it's almost OK.

The change in velocity (y-component) is (vf)y - 2.855×106 .

You have these reversed.
 
  • #30
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ohhhh gotcha, and I guess I should start using those parentheses more often hehe.

So solving for Vfy I get that it is about 2.34137 E6
 
  • #31
SammyS
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I think that's about right.
 
  • #32
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ok the numerical value is correct but the units are still wrong! lol
 
  • #33
SammyS
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ok the numerical value is correct but the units are still wrong! lol
You're now answering a question regarding velocity, not position so it has different units than the last time you asked about units.
 
  • #34
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* face palm * I need to stop doing homework so late, I got it now. Thank you soooo much for your help and time. I really appreciate it! This will certainly be a question I'll review for an upcoming exam :smile:
 
  • #35
SammyS
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* face palm * I need to stop doing homework so late, I got it now. Thank you soooo much for your help and time. I really appreciate it! This will certainly be a question I'll review for an upcoming exam :smile:
You're welcome.

Time for me to get some sleep too.
 

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