A screen for detecting electrons

[C6ZR1]

So in that case would it be 2.855 E6?

 

[SammyS]

So in that case would it be 2.855 E6?

No.

How much does the (negative) acceleration decrease the vertical component of the velocity in a time of 5.47×10^-7 seconds?

 

[C6ZR1]

well if acceleration is the change in velocity/ time then would it be -9.39E11= 2.855 E6- vy/ 5.47×10-7 ?

 

[SammyS]

well if acceleration is the change in velocity/ time then would it be -9.39E11= (2.855 E6- vy)/ 5.47×10^-7 ?

If you use parentheses correctly, it's almost OK.

The change in velocity (y-component) is (v_f)_y - 2.855×10⁶ .

You have these reversed.

 

[C6ZR1]

ohhhh gotcha, and I guess I should start using those parentheses more often hehe.

So solving for Vfy I get that it is about 2.34137 E6

 

[SammyS]

I think that's about right.

 

[C6ZR1]

ok the numerical value is correct but the units are still wrong! lol

 

[SammyS]

ok the numerical value is correct but the units are still wrong! lol

You're now answering a question regarding velocity, not position so it has different units than the last time you asked about units.

 

[C6ZR1]

* face palm * I need to stop doing homework so late, I got it now. Thank you soooo much for your help and time. I really appreciate it! This will certainly be a question I'll review for an upcoming exam

 

[SammyS]

* face palm * I need to stop doing homework so late, I got it now. Thank you soooo much for your help and time. I really appreciate it! This will certainly be a question I'll review for an upcoming exam

You're welcome.

Time for me to get some sleep too.