A shaft is required to transmit 60kW of power at 4000rev/Minute. Find

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SUMMARY

The discussion focuses on calculating the external diameter of a hollow shaft required to transmit 60 kW of power at 4000 revolutions per minute (RPM), with an internal diameter that is three-quarters of the external diameter and a maximum permissible shear stress of 48 MPa. Key equations include the relationship between torque and power, where power (P) equals torque (T) multiplied by angular velocity (ω). The necessary calculations involve determining torque from the given power and RPM, followed by applying shear stress formulas to find the external diameter.

PREREQUISITES
  • Understanding of torque and power relationships in mechanical systems
  • Familiarity with shear stress calculations
  • Knowledge of hollow shaft design principles
  • Basic proficiency in using equations of motion and mechanics
NEXT STEPS
  • Research the formula for calculating torque from power: T = P / ω
  • Study shear stress equations applicable to hollow shafts
  • Learn about the design considerations for hollow shafts in mechanical engineering
  • Explore the impact of varying internal diameters on shaft strength and performance
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Mechanical engineers, students in engineering mechanics, and professionals involved in shaft design and power transmission systems will benefit from this discussion.

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A shaft is required to transmit 60kW of power at 4000rev/Minute. Find the external diameter required for a hollow shaft if its internal diameter is three quarters of the external diameter. And the maximum permissible shear stress is 48MPa.


can someone help i am confused haven't got a clue how to do it
 
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What are the relevant equations do you think you will need?

How do you relate torque and power?
 

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