A simple question about Covalent Bond and Ionic Bond

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The discussion centers on the concept of variable valencies in chemistry, specifically focusing on the compounds cuprous chloride (CuCl) and cupric chloride (CuCl2). It explains how copper exhibits different valencies in these compounds, with CuCl having a valency of one and CuCl2 a valency of two. The question posed is whether the strength of the Cu-Cl bond differs due to the varying charges, and if chlorine would be easier to isolate from CuCl compared to CuCl2. Responses indicate that the bond strength is not necessarily dependent on the number of bonds but rather on the bond dissociation energy. Data presented shows trends in bond dissociation energies for various transition metal halides, suggesting that higher oxidation states generally lead to easier removal of halides. The conversation also touches on the importance of distinguishing between electric and magnetic charges in this context.
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I started reading a book about the basic foundations of chemistry, and I came up across a simple question.

To answer this question you should understand that there are variable valencies, which is what this question consists of.

If you look at the cuprous chloride compound CuCl, copper has a valency of one.

Chlorine will "take" an electron from the Copper atom, which forms a covalent bond. When taking the electron the overall magnetic charge of the chlorine atom is negative (let's say -1), and Copper is now overall positive (+1).

If we look at a slightly different compound cupric chloride CuCl(2), copper has a valency of 2.

Chlorine 1 and 2 will now take each an electron, so you have two with an overall charge of -1. Copper now gives two away, on its own, and now has an overall charge of +2.

My question is...

Is one bond stronger than the other because of magnetic charge?

In other words, would Chlorine be easier to isolate from the CuCl compound than the CuCl(2) compound, or molecule?

Thanks, for any answers.
 
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Anyone?

This is a simple question in which I am pondering.
 
I'm not sure because I'm no expert but I think that the Cu-Cl bond is identical regardless of how many bonds there are. So it'd require just as much energy to break any Cu-Cl bond.
 
chemistry always contains of mystery...
 
JasonRox said:
I started reading a book about the basic foundations of chemistry, and I came up across a simple question.

To answer this question you should understand that there are variable valencies, which is what this question consists of.

If you look at the cuprous chloride compound CuCl, copper has a valency of one.

Chlorine will "take" an electron from the Copper atom, which forms a covalent bond. When taking the electron the overall magnetic charge of the chlorine atom is negative (let's say -1), and Copper is now overall positive (+1).

You are referring to an electric charge... not magnetic.

If we look at a slightly different compound cupric chloride CuCl(2), copper has a valency of 2.

Chlorine 1 and 2 will now take each an electron, so you have two with an overall charge of -1. Copper now gives two away, on its own, and now has an overall charge of +2.

My question is...

Is one bond stronger than the other because of magnetic (electric) charge?

In other words, would Chlorine be easier to isolate from the CuCl compound than the CuCl(2) compound, or molecule?

Thanks, for any answers.

Let's look at trends in the transition metal halide series


Bond Bond dissociation energy (kJmol-1)
Ti-Cl (TiCl4) 429.3
Ti-Cl (TiCl3) 460.2
Ti-Cl (TiCl2) 504.6
Fe-F (FeF3) ~456
Fe-F (FeF2) 481
Fe-Cl (FeCl3) 341.4
Fe-Cl (FeCl2) 400.0
Fe-Br (FeBr3) 291.2
Fe-Br (FeBr2) 339.7
Fe-I (FeI3) 233.5
Fe-I (FeI2) 279.1
Cu-Cl (CuCl2) 293.7
Cu-Cl (CuCl) 360.7
Cu-Br (CuBr2) ~259
Cu-Br (CuBr) 330.1
Cu-I (CuI2) ~192
Cu-I (CuI) ~142

Clearly the trend is that the higher the oxidation state, the easier it is to remove the first halide in transition metals.
 
Necrophilia :smile:
 
A thread dig from 2004? That was long before I was even a member here
 
Opps! I keep forgetting to check that...
 
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