A small problem with complex conjugations

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The discussion centers on the understanding of complex conjugations in equations involving complex numbers. The equation zz* = (a2 + b2) is clarified as correct without the need for an imaginary unit, as z* represents the conjugate of z. The participant explains that when multiplying a complex number by its conjugate, the result simplifies to a real number, specifically a² + b². This highlights that the imaginary part cancels out during the multiplication process. The explanation resolves the initial confusion regarding the absence of an imaginary number in the equation.
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Hi!

I have a problem with understanding an equation which is really simple.

zz*=(a2+b2)

shouldn't there be an i there if

z1z2=(a1+ib1)(a2+ib2)

is the equation correct?

If it is could someone explain to me why there is no imaginary number?

Thank You!
 
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if z = a + bi, then z* (conjugate of z) = a - bi so

(z)(z*) = (a+bi)(a-bi) = a2 - (bi)2 = a2 -(i)2b2 = a2 -(-1)b2 = a2 + b2
 
Yes I can see that now.

Thanks!
 
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