A stone is dropped from the top of a cliff

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A stone dropped from a cliff takes 3.30 seconds to hit the ground. The height of the cliff can be calculated using the equation h = v_0 t + (1/2)gt^2, with an initial velocity (v_0) of 0 and g as the acceleration due to gravity. The discussion emphasizes that this type of question is more appropriate for the homework section of the forum. Participants are directed to continue their discussion in the designated area. The thread has been closed to maintain organization.
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A stone is dropped from the top of a cliff. It is seen to hit the ground below after 3.30 s. How high is the cliff?
 
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Use the equations of motion:
h = v_0 t + \frac{1}{2}gt^2
Where v_0 is the initial velocity (=0) and g is the acceleration due to gravity.
 
Oy! Some people never learn!

The identical question was moved to the HOMEWORK section where it belongs. Please continue there. This thread is closed.

https://www.physicsforums.com/showthread.php?t=86574

Zz.
 
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