A strange thing my professor told me about expectation

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Discussion Overview

The discussion revolves around the relationship between the expectation of a random variable E[X] and the expectation of its absolute value E[|X|], particularly in the context of continuous random variables. Participants explore definitions and implications of these expectations, especially in cases involving Cauchy distributions.

Discussion Character

  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant questions whether E[|X|] must be finite if E[X] = 0, citing their professor's statement as confusing.
  • Another participant notes that if E[|X|] is infinite, some definitions imply that E[X] does not exist, highlighting the subtleties involved.
  • A participant provides an example of the Cauchy distribution, stating that E[X] can equal 0 due to symmetry, even though E[|X|] is infinite.
  • One participant reflects on the textbook definition of expectation, which requires the integral of the absolute value to be finite for E[X] to be defined.
  • A later reply challenges the assertion that E[X] = 0 for Cauchy distributed variables, arguing that E[X] does not exist in this case, comparing it to an improper integral that does not converge.

Areas of Agreement / Disagreement

Participants express differing views on the existence of E[X] for Cauchy distributions and the implications of E[|X|] being infinite. The discussion remains unresolved, with multiple competing interpretations of the definitions and properties of expectation.

Contextual Notes

There are limitations regarding the definitions of expectation and the conditions under which they apply, particularly in relation to improper integrals and specific distributions like the Cauchy distribution.

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Suppose you know E[X] = 0 for a given (continuous) random variable. Does that mean E[|X|] < \infty? This is what my professor told me today, though it doesn't really make much sense...
 
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It is a subtle point. If E(|X|) is infinite, then according to some definitions, E(X) does not exist.
On the other hand if the distribution is Cauchy { density 1/[π(1+x2)]}, then E(X)=0 by symmetry even though E(|X|) is infinite.
 
mathman said:
It is a subtle point. If E(|X|) is infinite, then according to some definitions, E(X) does not exist.
On the other hand if the distribution is Cauchy { density 1/[π(1+x2)]}, then E(X)=0 by symmetry even though E(|X|) is infinite.
Ok, thanks. Looking back in our textbook, the definition of "expectation" begins: "Suppose \int_\Omega |X(\omega)| dP(\omega) <\infty. Then we define the expectation..." So I guess that's the way it is!
 
mathman said:
It is a subtle point. If E(|X|) is infinite, then according to some definitions, E(X) does not exist.
On the other hand if the distribution is Cauchy { density 1/[π(1+x2)]}, then E(X)=0 by symmetry even though E(|X|) is infinite.

If X is Cauchy distributed, then E[X] doesn't exist. So saying E[X]=0 is wrong there. It's as wrong as saying \int_{-\infty}^{+\infty}{xdx}=0. The integral simply does not exist.
 

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