A sum I wish I never came across

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The discussion revolves around the convergence of the summation lim_{\stackrel{\Delta t \rightarrow 0}{n \rightarrow \infty}}\left(\Delta t \sum_{k=0}^n x^k\right) as x approaches 1 from the left. It is noted that the sum resembles the Maclaurin series for (1-x)^{-1}, which diverges to +∞ as x approaches 1. However, the presence of \Delta t approaching 0 complicates the limit's behavior. Participants clarify that if n, x, and \Delta t vary independently, the limit does not exist, but if interrelations are established, the outcome may differ. Ultimately, it is concluded that if x is less than 1, the sum converges.
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I've come across the following summation

lim_{\stackrel{\Delta t \rightarrow 0}{n \rightarrow \infty}}\left(\Delta t \sum_{k=0}^n x^k\right)

moreover, as \Delta t \rightarrow 0, x\rightarrow 1^-

Does the sum converge? to what?

My thoughts...
The sum as n \rightarrow \infty is simply the Mclaren series of (1-x)^{-1}, so as x \rightarrow 1^-, the sum should diverge to + \infty, however, we have the \Delta t in the front that \rightarrow 0, and that's as far as my intellect takes me...
any ideas?
 
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dt doesn't seem to participate in the expression, did you forget it somewhere?
 
elibj123 said:
dt doesn't seem to participate in the expression, did you forget it somewhere?

Yes, I'm so sorry. Its fixed now.
 
You have three variables, n, x, and \Delta t.

If they are all allowed to vary independently, the limit does not exist - you can construct sequences of (n,x,\Delta t) which approach any number you want.

If there are some interrelations between them, that's a different story.
 
Apteronotus said:
My thoughts...
The sum as n \rightarrow \infty is simply the Mclaren series of (1-x)^{-1}, so as x \rightarrow 1^-, the sum should diverge to + \infty, however, we have the \Delta t in the front that \rightarrow 0, and that's as far as my intellect takes me...
any ideas?

if x < 1 it converges.
 
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