zhanhai said:
Can we simply understand a softened phonon mode as one having reduced energy/frequency?
Does "soft" indicate smaller value of the spring coefficient like the k in
f=kx,
where f is force and x is displacement of a spring, so a "soft" spring has a smaller k value?
Thanks for all help.
The "soft" indicates that the spring has "broken", not that its elasticity has changed. If the value of k merely changed, the spring could still vibrate as long as the vibrations are centered on the site of attachment of the spring. If the spring breaks, the bob can drift anywhere. The spring is softer because it has ceased to exist, not because its tension has changed.
The decrease in frequency does not come from a change in k, but from a loss of order. Changing the value of k does not change the degree of order in the system. Changing the value of k is like a change without a phase transition. The breaking of the spring is very much like a phase transition.
It is not complete to say that a soft phonon mode corresponds to a decrease in phonon frequency. I think it is more correct to say that the soft phonon mode corresponds to a decrease in crystal symmetry. The decrease in phonon frequency is a consequence of the decrease in crystal symmetry. The decrease in crystal symmetry is usually associated with a certain type of phase transition.
Soft phonons are usually associated with phase transitions in crystals that have more than one distinguishable lattice. There is a lattice associated with each atom of a unit cell which is distinguishable from the lattices associated with the other atoms of the unit cell. As long as all the lattices are intact, the crystal will have a band structure that includes several kinds of optical phonons. If one of the lattices becomes disordered, leaving the other lattices intact, the optical phonons associated with the disordered lattice become acoustical phonons. The optical phonon associated with the disordered phonon is referred to as a soft phonon.
Look at the phase transition as a type of partial melting. One of the lattices melts while the other lattices remain solid. While the crystal is entirely frozen, there will be transverse optical phonons associated with vibrations within each lattice. Each optical phonon has a finite frequency at zero wave vector. However, suppose one of the lattices melts. Liquids can’t support transverse waves, and neither can this melted lattice. Obviously, the vibrations associated with that transverse mode can no longer occur. So the zero wave vector frequency of this phonon has to become zero when that lattice “melts”.
Before the lattice melted, the crystal had a high degree of symmetry. The equilibrium point of every atom was restricted to a specific point on the unit cell and on the lattice. After a lattice melts, the atoms in that lattice can diffuse anywhere in the crystal. Thus, the crystal has a very low degree of symmetry after the transition. Therefore, the soft phonon mode is closely associated with the symmetry of the crystal before and after the phase transition.
Diffusion is one difference between what you are saying and the reality of soft phonons. In a crystal that isn’t undergoing a phase transition, the phonon could decrease in frequency without the associated atoms diffusing. One can heat or stress the crystal resulting in a lower phonon energy, and there will be no atoms diffusing. However, if one of the lattices becomes disordered, the atoms in that lattice can diffuse. So the decrease in frequency during this phase transition signals the onset of diffusion.
Here are some links concerning soft phonons and phase transition.
http://hal.archives-ouvertes.fr/docs/00/22/19/47/PDF/ajp-jphyscol198243C403.pdf
“The concept of "soft phonon" associated with a phase transition signifies a phenomenon in which a phonon mode, which coincides with a lower-symmetry structure, is very much amplified immediately before the onset of phase transition from a higher-symmetry structure.”
http://webspace.webring.com/people/ra/astrophys0msci/CrystalStructure_Handout10_0.pdf
“Zone-boundary phonons: When the distortion is driven by a zone-boundary phonon, the distorted structure will have a larger unit cell (the translational symmetry is broken). The 12 zone boundary point will then “fold” to the new zone center, and the soft phonon will harden below the phase transition to become a new zone center phonon.”
http://www.riken.jp/lab-www/library/publication/review/pdf/No_29/29_034.pdf
“The soft phonon phase transition is one of the best established mechanisms by which a crystal structure can change. In the pressure-induced case, the frequency of a given vibration in the lattice goes to zero as the transition is approached: zero frequency implies that the lattice structure is unstable, and will transform, typically to a lower symmetry phase.”