About uniform electric field between parallel plates

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The electric field between parallel plates is independent of distance only for ideal infinitely long plates, as derived from Gauss's law. When the distance between the plates increases, the voltage also changes if the plates are insulated, affecting the electric field. However, if a constant potential difference is maintained, the electric field remains consistent despite changes in distance. The relationship E=V/d indicates that while the electric field can be constant, the voltage will increase with distance. Thus, the electric field's independence from distance applies under specific conditions related to the plates' configuration and the voltage source.
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I have learned that the electric field between parallel plates are independent of distance
since E=V/d
so if I increase the distance between parallel plates, the E will decrease, right?
if I am right on the previous statement, then why does the electric field are independent of distance?
 
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curiosity colour said:
I have learned that the electric field between parallel plates are independent of distance

Are you sure that isn't for ideal infinitely long parallel plates?
 
Drakkith said:
Are you sure that isn't for ideal infinitely long parallel plates?

You are right. This is only for such plates and can be derived using Gauss' law. If we neglect rand effects, we can still use it as an approximation for smaller plates, though.
 
Drakkith said:
Are you sure that isn't for ideal infinitely long parallel plates?
The textbook just wrote parallel plates, didn't said anything about ideal infinitely long parallel plates
So only if parallel plates are infinitely long, the electric field between parallel plates are independent of distance ? Still though, why is that?
 
curiosity colour said:
The textbook just wrote parallel plates, didn't said anything about ideal infinitely long parallel plates
So only if parallel plates are infinitely long, the electric field between parallel plates are independent of distance ? Still though, why is that?

Do you know Gauss' law? (one of the maxwell equations, ##\iint_S \vec E . \vec{dA} = \frac{Q_{enc}}{\epsilon_0}## where we integrate over a closed surface ##S##)
 
Math_QED said:
Do you know Gauss' law? (one of the maxwell equations, ##\iint_S \vec E . \vec{dA} = \frac{Q_{enc}}{\epsilon_0}## where we integrate over a closed surface ##S##)
Yeah, I know about Gauss's law
 
curiosity colour said:
I have learned that the electric field between parallel plates are independent of distance
since E=V/d
so if I increase the distance between parallel plates, the E will decrease, right?
if I am right on the previous statement, then why does the electric field are independent of distance?
If the plates are insulated, the Potential difference will change as you separate them so the V in "E=V/d" will change. (The Capacitance C will change and V=Q/C applies)
If you connect a source of PD to the plates, to maintain V then E=V/d will apply. So there is no contradiction.
 
curiosity colour said:
I have learned that the electric field between parallel plates are independent of distance
since E=V/d
so if I increase the distance between parallel plates, the E will decrease, right?
if I am right on the previous statement, then why does the electric field are independent of distance?
The E field is independent of the distance, but the voltage is not. The E field is the gradient of the voltage, so if you have the same E field over a larger distance then you have a greater voltage.
 
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