delsoo said:Homework Statement
a resistor of 1000 ohm is connected in series to a capacitor and ac supply of frquency 50hz, if the phase diffennce of voltage supplied and current of circuirt is 30 degree, what's the capacitance of capacitor? the V max and I max in not given , how to do this ? help please!
Homework Equations
The Attempt at a Solution
delsoo said:since the reacatance(X c ) =V max/ I max . i let r = 1000 ohm = resistance, Xc also = //2pI (f)(C) , so i got 1000=1/2pi (50) (c) , but i don't know where to sub the 30 degree..
AC voltage across a capacitor refers to the alternating current voltage that is present on the plates of a capacitor. It is a measure of the difference in potential between the two plates and is measured in volts.
AC voltage affects a capacitor by causing charge to build up on the plates, creating an electric field between them. As the voltage alternates, the charge on the plates also alternates, causing the capacitor to charge and discharge.
The relationship between AC voltage and capacitance is described by the equation Q=CV, where Q is the charge on the capacitor, C is the capacitance, and V is the voltage. As the voltage increases, the charge on the capacitor also increases.
The frequency of AC voltage affects the capacitor by determining how quickly the voltage alternates and how often the capacitor charges and discharges. Higher frequencies will result in a faster charging and discharging process, while lower frequencies will have a slower effect on the capacitor.
The phase relationship between AC voltage and the capacitor's current is 90 degrees. This means that the current leads the voltage by 90 degrees in a capacitor. This is due to the fact that the capacitor's current is directly proportional to the rate of change of the voltage, and as the voltage is changing the fastest, the current is at its peak.