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I think the answer to the first question is yes, and to the second one : 1s.

What do you think about that ?

Thanks

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- Thread starter Omid
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- #1

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I think the answer to the first question is yes, and to the second one : 1s.

What do you think about that ?

Thanks

- #2

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- #3

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Yes it would remain constatn.

- #4

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No... What is the definition of acceleration?

- #5

Tide

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Are you sure?

- #6

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Tide said:Are you sure?

Who are you asking?

- #7

BobG

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The answer to the first is 'No'. The answer to the second is '1 sec'.Omid said:

I think the answer to the first question is yes, and to the second one : 1s.

What do you think about that ?

Thanks

If the cars are accelerating at a constant rate, they cover more ground each second than they did the previous second.

If they are accelerating at 2 m/s^2:

After 1 sec, the first has moved 1 meter - the second 0.

After 2 sec, the first has moved 4 meters - the second 1 meter.

After 3 sec, the first has moved 9 meters - the second 4 meters.

And so on.

- #8

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At any given time the velocities of the two falling bodies will not be the same. The one dropped first will have a greater V at time 1 than the second body. If you look at acc. of each body with respect to the earth the acc. will be the same. Look at the acc. of one body with respet to the other and you see that the acc is constantly changing.

[tex]\vec{a}_{rel}=\frac{dv_{rel}}{dt}[/tex]

When doing comparisons like this you need to look at the bodies in relation to each other and not in relation to a third body (usually).

Good luck.

- #9

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Thanks a lot

- #10

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So they are closest to each other after first second, aren't they ?

- #11

Tide

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faust9 said:Who are you asking?

Sorry - I was asking Omid who stated the separation would be constant. I didn't notice you had slipped in there before I posted it.

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