Acceleration and Distance problem

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A turtle accelerates along a straight ditch, taking 10 seconds to travel 10 meters to a pine tree, reaching a speed of 1.2 m/s. The acceleration calculated is 0.04 m/s². To find the distance from the fence post where the turtle started from rest, the first equation of motion can be applied using the initial velocity of 0 m/s and the final velocity of 0.8 m/s. This approach leads to the solution for the distance traveled from the fence post. The discussion emphasizes the importance of correctly applying the equations of motion to solve the problem.
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Homework Statement


A turtle is moving with constant acceleration along a straight ditch. He starts his stopwatch as he passes a fence post and notes that it takes him 10s to reach a pine tree 10m further along the ditch. As he passes the pine tree, his speed is 1.2m/s. How far was he from the fence post when he started from rest?

Homework Equations


V22=V12+2a\Deltad
\Deltad=V1\Deltat+1/2a(\Deltat)2
\Deltad=V2\Deltat-1/2a(\Deltat)2


The Attempt at a Solution



So I found out acceleration using the third equation, which is .04 m/s2. So now I believe I have to figure out the velocity at the fence post, which comes to 0.8 m/s. I don't know what to do after that.
 
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You've already done all the work. All they are asking you is to solve for the distance the turtle traveled from rest to the fence post. Just use equation 1 with V1 = 0, V2 = 0.8 m/s, and a = .04 m/s^2.
 
Bhumble said:
You've already done all the work. All they are asking you is to solve for the distance the turtle traveled from rest to the fence post. Just use equation 1 with V1 = 0, V2 = 0.8 m/s, and a = .04 m/s^2.

Oh. Yeah I see that now thanks.
 
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