Acceleration and maximum range

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Homework Help Overview

The discussion revolves around calculating the acceleration and maximum range of a frog's jump, given a maximum vertical height of 0.28m and an acceleration distance of 0.086m. The gravitational constant is noted as 9.81 m/s², and there is mention of a 45-degree launch angle.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants explore the interpretation of the maximum vertical height and its relation to the jump's angle. There are questions about the clarity of the task and the assumptions regarding the take-off speed and angle.

Discussion Status

Some participants are attempting to clarify the original problem statement and its implications. There is an ongoing exploration of the relationship between the take-off speed, angle, and the resulting height and range of the jump. Suggestions for further analysis are being made without reaching a consensus.

Contextual Notes

There is a noted lack of information regarding the take-off speed, which is crucial for solving the problem. Participants express uncertainty about the task's requirements and the potential for misinterpretation due to translation issues.

bolskipolski
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How do you calculate the acceleration and the maximum range of a jump (in this case a frog,) when the maximum vertical height is 0.28m and the distance of acceleration is 0.086 m? I also tried to use the 45 degree, and the gravitation constant 9,81 m/s^2 but can't get it right..
 
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Is the max vertical height that's given for a vertical jump? For a 45 degree jump? Something else?
 
haruspex said:
Is the max vertical height that's given for a vertical jump? For a 45 degree jump? Something else?

I don't have any more info, so I don´t know
 
Pls post the question as posed, word for word. You might be missing something in the interpretation.
 
haruspex said:
Pls post the question as posed, word for word. You might be missing something in the interpretation.

Task 2: Calculate the acceleration and maximum range of a jump in the case of a frog. The maximum vertical height is 0.28m and the distance of acceleration is 0.086m. The gravity constant g=9.81 m/s^2

This is the task i got (word for word), nothing less nothing more
 
Ok, I read that as meaning the height given is for a jump of max range. (It's not entirely clear, but I think that's a fair reading.)
Suppose the take-off speed is u. What would the max range be? What height would be reached?
 
haruspex said:
Ok, I read that as meaning the height given is for a jump of max range. (It's not entirely clear, but I think that's a fair reading.)
Suppose the take-off speed is u. What would the max range be? What height would be reached?

could be, yes. my teacher don´t speak english, so he translates all the tasks in google translate ... Honestly, i have no clue what he is asking for.
So, i don't know, i don't know i don't know, and i am sorry for not answering your questions.
I just need a suggestion
 
You mentioned a 45 degree take-off. What made you suggest that?
 
haruspex said:
You mentioned a 45 degree take-off. What made you suggest that?

I read in a physicbook that the maximum distance of movement of an object in 2 dimensions, irrespective of wind resistance, the angle will always be equal to 45
(as evidenced by sin2 * 45 = 1)
 
  • #10
On a level surface, yes. (It's different going up or down an incline.)
So assuming 45 degrees, and a take-off speed of u, what would the height and range be?
 
  • #11
haruspex said:
On a level surface, yes. (It's different going up or down an incline.)
So assuming 45 degrees, and a take-off speed of u, what would the height and range be?

I don't have any take-off speed. The height i guess would be 0.28, the range could be the distance (0.086) ?
 
  • #12
bolskipolski said:
I don't have any take-off speed.
I know that. I wrote, let the take-off speed be u, an unknown. If the take-off angle is 45 degrees, what is the vertical component of speed at take-off (as a function of u)? What kinematic equations do you have relating distance, constant acceleration and initial and final speeds? Using that, what height would be reached (as a function of u)? Knowing the height the frog does reach, what value does that give you for u?
the range could be the distance (0.086) ?
No, that's the distance through which the frog was accelerating during its take-off. After you've worked out the take-off speed, you can use it in the following ways:
- find out how long the frog takes to land, and thus how far he jumps
- find out what the acceleration must have been during the take-off period.
 

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