Acceleration due to gravity

  • Thread starter hovno1
  • Start date
  • #1
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1. On an asteroid a small object falls, from rest, 1.00m in 4.20s. What is the acceleration due to gravity on the surface of the asteroid?



2.



3. I am getting an answer of 5.67 * 10^-2, by dividing the velocity (distance/time) by the time. Is this the correct?

I will really appreciate any feedback!
 

Answers and Replies

  • #2
648
2
Acceleration is change in velocity divided by time taken.
Dividing that distance by the time taken would calculate the average velocity of the falling object, not the change in its velocity.
Do you know any equations for uniformly accelerated motion?
 
  • #3
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think ive done it now using the equation (Vf-Vi)/t=g. Is this the correct equation to use?
 
  • #4
lanedance
Homework Helper
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not quite, as you don't know the final velocity (though you can work it out), howevere, you do know the distance it travelled, usually called 's' or 'x'
 
  • #5
hunt_mat
Homework Helper
1,741
25
The equation to use here is:
[tex]
x=\frac{1}{2}gt^{2}
[/tex]
As the initial speed was zero.
 

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